Answer:
H =2; I = 2; J = 2
Explanation:
Carbon is element 6 in the Periodic Table.
Start at element 1 (H) and count from left to right until you reach element 6 (C).
You get the electron configuration
C: 1s² 2s²2p².
Thus,
H =2; I = 2; J = 2
In the reaction Zn + CuSO₄ → Cu + ZnSO₄
1 answer:
The given question is incomplete. The complete question is:
In the reaction , identify the oxidizing and reducing agent.
Answer: reducing agent. : Zn
oxidizing agent :
Explanation:
Oxidation reaction : When there is an increase in oxidation state number.
Reduction reaction : when there is a decrease in oxidation state number.
Zinc metal has undergone oxidation, as its oxidation state is changing from 0 to 2+. Zinc metal is getting converted into zinc ions.
ions has undergone reduction, as its oxidation state is changing from +2 to 0. Copper ions are getting converted into copper metal.
The chemical agent which itself get oxidized and reduce others is called reducing agent.
is a reducing agent.
The chemical agent which itself get reduced and oxidize others is called oxidizing agent. is an oxidizing agent.
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Answer:
The rabbit population will reach 500 after 10 months.
Explanation:
According to the given data:
The initial number of rabbit's equals 2.
Number of rabbit's after 2 months =2x3= 6
Number of rabbit's after 4 months = 6x3=18
Number of rabbit's after 6 months = 18x3=54
Number of rabbit's after 8 months = 54x3=162
Thus we can see that the number of rabbit's form a Geometric series with common ratio =3 and initial term = 2
Now the general term of a geometric series with first term 'a' and common ratio 'r' is given by
Thus we need to find when the term becomes 500 thus using the given data we have
Thus the fifth term (excluding the start term) will have a rabbit count of 500 now since each term has a time difference of 2 months thus sixth term will occur after