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almond37 [142]
3 years ago
9

In the reaction Zn + CuSO₄ → Cu + ZnSO₄

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
7 0

The given question is incomplete. The complete question is:

In the reaction Zn+CuSO_4\rightarrow Cu+ZnSO_4, identify the oxidizing and reducing agent.

Answer:  reducing agent. : Zn

oxidizing agent : CuSO_4

Explanation:

Oxidation reaction : When there is an increase in oxidation state number.

Reduction reaction : when there is a decrease in oxidation state number.

Zinc metal has undergone oxidation, as its oxidation state is changing from 0 to 2+. Zinc metal is getting converted into zinc ions.

Cu^{2+} ions has undergone reduction, as its oxidation state is changing from +2  to 0. Copper ions are getting converted into copper metal.

The chemical agent which itself get oxidized and reduce others is called reducing agent.   Zn is a reducing agent.

The chemical agent which itself get reduced and oxidize others is called oxidizing agent. CuSO_4 is an oxidizing agent.

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A compound consisting of B, N, and H undergoes elemental analysis. The % composition by mass is found to be 40.28% B, 52.20% N,
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Empirical formula is the simplest ratio of components making up a compound.

The percentage composition of each element has been given

therefore the mass present of each element in 100 g of compound is

                      B                                   N                         H

mass          40.28 g                         52.20 g                 7.53 g

number of moles  

                 40.28 g / 11 g/mol      52.20 g / 14 g/mol    7.53 g / 1 g/mol

                = 3.662 mol                  = 3.729 mol             = 7.53 mol

divide the number of moles by the least number of moles, that is 3.662

                3.662 / 3.662              3.729 / 3.662              7.53 / 3.662

               = 1.000                           = 1.018                        = 2.056

the ratio of the elements after rounding off to the nearest whole number is

B : N : H = 1 : 1 : 2

therefore empirical formula for the compound is B₁N₁H₂          

that can be written as BNH₂    

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