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julsineya [31]
3 years ago
9

For a certain chemical reaction, the bond energy of the reactants is 43 kJ, and 35 kJ of energy is released. For energy to be co

nserved, what is the bond energy of the products?
Chemistry
2 answers:
ASHA 777 [7]3 years ago
8 0

Answer:

78kJ

Explanation:

Energy change = Energy in (reactants) - Energy out (products)

According to this question, energy is released, meaning that the reaction is EXOTHERMIC. Hence, the energy change will be negative (-) i.e bond energy of reactants is greater than bond energy of products.

Energy in = bond energy of reactants = 43kJ

Energy out = bond energy of products = ?

Energy change of exothermic reaction = -35kJ

Therefore;

-35kJ = 43kJ - x

x = 35kJ + 43kJ

x = 78kJ

The bond energy of the products is 78kJ.

storchak [24]3 years ago
6 0

Answer: 78 kJ

Explanation:

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Answer:

Avogadro’s Number

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3 0
3 years ago
Read 2 more answers
What is the partial pressure of radon if the total pressure is 780 torr and the
Brilliant_brown [7]

Answer:

0.03atm

Explanation:

Given parameters:

Total pressure  = 780torr

Partial pressure of water vapor  = 1.0atm

Unknown:

Partial pressure of radon  = ?

Solution:

A sound knowledge of Dalton's law of partial pressure will help solve this problem.

The law states that "the total pressure of a mixture of gases is equal to the sum of the partial pressures of the constituent gases".

Mathematically;

           P_{t}   =   P_{1}  + P_{2}   +   P_{n}

Since the total pressure is 780torr, convert this to atm;

                       760torr = 1 atm

                       780torr  = \frac{780}{760} atm  = 1.03atm

     For this problem;

Total pressure  = Partial pressure of radon + Partial pressure of water vapor

            1.03 = Partial pressure of radon + 1.0

  Partial pressure of radon  = 1.03 - 1.00  = 0.03atm

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