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nata0808 [166]
3 years ago
10

A body initially moving with a speed of 20m/s covers a distance of 150m after 5 sec .What is the acceleration of the body?

Physics
1 answer:
alisha [4.7K]3 years ago
6 0

Answer:

a=4m/s2

Explanation:

Vi= 20m/s

S=150 m

t= 5 sec

a=?

using 2nd equation of motion;

S= Vit+0.5at^{2}

putting values

150= (20)(5)+0.5(a)(5^{2})

150-100= 12.5a

50/12.5 =a

4m/s2=a

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Below is a circuit schematic of sources and resistors (Figure 3). VS = 10V , R1 = 100Ω, R2 = 50Ω, R3 = 25Ω, IS = 2A. Calculate t
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V_3\approx 4.28\,\,V

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So we first find the equivalent resistance for the two resistors in parallel:

\frac{1}{Re}= \frac{1}{R1}+\frac{1}{R2}\\\frac{1}{Re}= \frac{1}{100}+\frac{1}{50}\\\frac{1}{Re}= \frac{3}{100}\\Re=\frac{100}{3} \,\,\Omega

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Vs=I\,*\,(\frac{100}{3} +25)\\10=I\,*\,\frac{175}{3} \\I=\frac{30}{175} \,amps

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V_3=\frac{30}{175} *\,25=\frac{30}{7} \approx 4.28\,\,V

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