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babunello [35]
3 years ago
15

You should ALWAYS carry the microscope by placing your hand on the base of the microscope and gripping the red handle with your

other hand. © True False​
Physics
1 answer:
marin [14]3 years ago
4 0

Answer:

true

Explanation:

place hand under base and one on the arm/handle

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A physics major is cooking breakfast when he notices that the frictional force between
White raven [17]
Let's list the given information. The frictional force, denoted as Ff, is equal to 0.200 N. We have to find the normal force, denoted as Fn. The relationship between Ff and Fn is written as:

Ff = μFn
where μ is the coefficient of friction

If there is no given data for μ, we can't solve this problem. Suppose μ = 0.5, then the normal force would be:
Fn = Ff/μ = 0.2/0.5 = 0.4 N
8 0
3 years ago
The graph in the accompanying figure (Figure 1) shows the magnitude of the force exerted by a given spring as a function of the
serious [3.7K]

The elastic potential energy stored in the stretched spring is 1 J.

<h3>What is Hooke's law?</h3>

Hooke's law states that; provided the elastic limit is not exceeded, the extension of the spring is directly proportional to the force on the spring.

Given that;

Force on the spring = 350 Newton

Distance stretched = 7 centimeters or 0.07 m

Hence;

F = ke

k = F/e = 350 Newton/0.07 m = 5000 N/m

Work done in stretching a spring = 1/2ke^2

= 0.5 × 5000 × (2 × 10^-2)^2 =1 J

Learn more about elastic potential energy: brainly.com/question/156316

4 0
2 years ago
Studies of the relationship of the Sun to our galaxy-the Milky Way-have revealed that the Sun is located near the outer edge of
lianna [129]

Mass of the milkyway galaxy :

M_{mw} = \frac{4\pi ^{2}r^{3}}{GT^{2}}\\\\M_{mw} = \frac{4\pi ^{2}(3x10^{4}x9.46x10^{15})^{3}}{6.67x10^{-11}Nm^{2}/Kg^{2}x(7.13x10^{15})^2}\\\\M_{mw } =  2.7x10^{14} Kg

The magnitude of the mass of the Milky Way galaxy = 2.7x10^{14} Kg

<h3>Can galaxies recycle stars?</h3>

Galaxies do not appear to have sufficient matter inside them to keep shaping modern stars at the rates that they do. Presently, astronomers have caught a universe within the act of reusing fabric that it already tossed out, which may clarify the discrepancy. New perceptions give the primary coordinate evidence of gas streaming into distant galaxies that are effectively making infant stars, offering support for the "galactic recycling" theory.

To learn more about galactic recycling, visit;

brainly.com/question/6272572

#SPJ4

6 0
2 years ago
. You have completed your design of a new surgical headlamp. You have decided to power the headlamp using four AA rechargeable b
SSSSS [86.1K]

Answer:

LED run before the batteries are depleted is 3.87 hours

Explanation:

given data

battery = 4 AA

battery is rated = 1.2V, 2550 mAh

power = 3 W

efficient = 95%

to find out

How long will the LED run before the batteries are depleted

solution

we consider here power delivered by battery is = x

so power = x × efficient

3 = x 95%

x = 3.15 W

and

voltage by 4 battery is = 4 × 1.2 = 4.8 V

so current will be = \frac{x}{volatge}

current = \frac{3.15}{4.8}

current = 0.6577 A

so total discharge hours = \frac{2550}{current}

total discharge hours = \frac{2550}{657.7}

time = 3.87 hours

so LED run before the batteries are depleted is 3.87 hours

5 0
4 years ago
AGREE OR DISAGREE: All light can be seen.
Tema [17]

Answer:

Disagree

Explanation:

We cannot see infared lights.

3 0
3 years ago
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