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babunello [35]
3 years ago
15

You should ALWAYS carry the microscope by placing your hand on the base of the microscope and gripping the red handle with your

other hand. © True False​
Physics
1 answer:
marin [14]3 years ago
4 0

Answer:

true

Explanation:

place hand under base and one on the arm/handle

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A 3.0 kg box is suspended by a series of ropes as shown below. The tension force in the horizontal rope is -40 N. What is the te
Nitella [24]

Answer:

50 N

Explanation:

Let the force in the horizontal rope be F₁ and the force in the diagonal rope be F₂:

The total force in the horizontal and vertical directions must be zero, since the object is at rest and is not accelerating.

The horizontal component of the forces:

F₁ + F₂ = -40N + F₂ = 0

F₂ = 40N

The vertical component of the forces:

F₁ + F₂ - mg = 0 + F₂ - mg = 0

F₂ = mg

If I assume the gravitational constant g = 10 m/s²:

F₂ = (3 kg) * (10 m/s²) = 30N

Adding the horizontal and vertical components of the force F₂:

F₂ = √((40N)² + (30N)²) = 50N

6 0
3 years ago
A science class puts a balloon containing 1.25 l of air at 101 kpa into a bell jar. using an air pump, the class removes some of
storchak [24]
The first thing you should know in this case is the following definition:
 PV = nRT
 Then, as the temperature is constant, then:
 PV = k
 Then, we have two states:
 P1V1 = k
 P2V2 = k
 We can then equalize both equations:
 P1V1 = P2V2
 Substituting the values:
 (1.25) * (101) = (2.25) * (P2)
 Clearing P2:
 P2 = ((1.25) * (101)) /(2.25)=56.11Kpa
 answer:
 the new pressure inside the jar is 56.11Kpa
8 0
3 years ago
The roller coaster is designed according to safety regulations that prohibit the speed of the car from exceeding 20 m/s. find th
hram777 [196]

maximum allowed value of the speed in roller coaster is given as

v = 20 m/s

now from kinematics we can say

v^2 - v_i^2 = 2 a s

here initial speed will be

v_i = 0

acceleration is due to gravity

a = 9.8 m/s^2

now we can use this to find the height

20^2 - 0^2 = 2 * 9.8* h

400 = 19.6 *h

h = 20.4 m

so maximum allowed height will be 20.4 m

4 0
3 years ago
If santa slides 5.00 m before reaching the edge, what is his speed as he leaves the roof?
AveGali [126]

Even with no friction, it depends on the slope of the roof. That is, it depends on how much elevation (altitude) he loses during the slide.

Whatever that number is ... call it 'h' ... Santa's speed when he reaches the edge is

Square root of (19.6h) meters per second.

It doesn't matter how much he weighs, or how far he has slud. Only how much altitude he lost on the slope while sliding.

8 0
3 years ago
How do I do these? Please help
ICE Princess25 [194]

Explanation:

4a)the displacement is the distance moved in a direction but since no direction is given, the displacement is equal to the distance

b) the distance moved is 400m because that's the length of the track

4 0
3 years ago
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