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2 years ago

What is the momentum of a 0.000015 kg mosquito flying straight at you with a velocity of 5.20 m/s?

Physics

1 answer:

Setler [38]2 years ago

3 0

Answer:

Momentum, $p=7.8\times 10^{-5}\ N-m$

Explanation:

Given that,

Mass of a mosquito, m = 0.000015 kg

Velocity of the mosquito, v = 5.2 m/s

We need to find the momentum of the mosquito. The momentum of an object is given by :

p = mv

Put all the values in the above formula.

$p=0.000015\ kg\times 5.2\ m/s\\\\p=0.000078\ N-m\\\\\text{or}\\\\p=7.8\times 10^{-5}\ N-m$

So, the momentum of the mosquito is $7.8\times 10^{-5}\ N-m$ .

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26.2/3.4 would be the average velocity for the run.

7.7 miles/hr

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2 years ago

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If Sarah melts 10g of tin. What mass of melted tin would she have at the end of the experiment?

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Answer:

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3 years ago

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Answer:

Kinetic Energy.

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2 years ago

The position of an object in simple harmonic motion is defined by the function y = (0.50 m) sin (πt/2). Determine the maximum sp

Gnoma [55]

The maximum speed of the object under simple harmonic motion is 0.786 m/s.

The given parameters:

Position of the particle, y = 0.5m sin(πt/2)

<h3>Wave equation for simple harmonic motion;</h3>

y = A sin(ωt + Ф)

where;

A is the amplitude = 0.5 m
ω is the angular speed = π/2

The maximum speed of the object is calculated as follows;

$V_{max} = A \omega\\\\V_{max} = 0.5 \times \frac{\pi}{2} = \frac{\pi}{4} \ m/s = 0.786 \ m/s$

Thus, the maximum speed of the object under simple harmonic motion is 0.786 m/s.

Learn more about simple harmonic motion here: brainly.com/question/17315536

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2 years ago

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Answer:

The width of the central bright fringe on the screen is observed to be unchanged is $4.48*10^{-6}m$

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