The elements in each group have the same number of electrons in the outer orbital<span>. Those </span>outer<span> electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements. Every element in the first column (group one) has one electron in its </span>outer<span> shell.</span>
Answer:
Yes, it is possible.
Explanation:
A diprotic acid is an acid that can release two protons. That's why it is called diprotic.
Monoprotic → Release one proton, for example Formic acid HCOOH
Triprotic → Releases three protons, for example H₃PO₄
Polyprotic → Release many protons, for example EDTA
it is a weak acid.
In the first equilibrum, it release proton, and the second is released in the second equilibrium. So the first equilibrium will have a Ka1
H₂A + H₂O ⇄ H₃O⁺ + HA⁻ Ka₁
HA⁻ + H₂O ⇄ H₃O⁺ + A⁻² Ka₂
The HA⁻ will work as an amphoterous because, it can be a base or an acid, according to this:
HA⁻ + H₂O ⇄ H₃O⁺ + A⁻² Ka₂
HA⁻ + H₂O ⇄ OH⁻ + H₂A Kb₂
Answer:
Yes
Explanation:
They continue to split and grow and split again until the organism that is carrying them dies.
Sorry I don't really know how to explain:(
The conversions that will be used are:
1 mole of copper / 63.5 grams of copper
6.02 x 10²³ atoms of copper / 1 mole of copper
Multiplying the given mass by these conversions,
660 g * (1 mol Cu / 63.5 g Cu) * (6.02 x 10²³ Cu atoms / 1 mole Cu)
The sample contains 6.25 x 10²⁴ atoms of copper
