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Pavel [41]
3 years ago
12

A substance of mass 200g measures 50cm*4cm*8cm. Calculate it density giving your answer in SI unit​

Physics
1 answer:
Oduvanchick [21]3 years ago
5 0

Answer:

0.2kg/0.0016m^3

Explanation:

200g is 0.2 kg

50*4*8 is equivalent to 1600 cubic centimeters which is also equivalent to 0.0016 cubic meters.

The SI unit for density is kg per cubic meter

So now we have 0.2kg/0.0016m^3

I hoped this helped, and if it did please give me brainliest

You might be interested in
A centrifuge accelerates uniformly from rest to 15000 rpm in 330 s . Through how many revolutions did it turn in this time?
eduard

Answer:

The number of revolutions turned by the centrifuge is 8250 revolutions.

Explanation:

Given;

number of revolution per minutes, ω = 15000 rpm

time of  motion, t = 330 s = 5.5 minutes

The number of revolutions turned by the centrifuge is given by;

N = \frac{1500 \ Rev}{minutes} *5.5 \ minutes\\\\N = 8250 \ revolutions

Therefore, the number of revolutions turned by the centrifuge is 8250 revolutions.

4 0
3 years ago
a teacher studies how the number of absent affects the final grade of their students. what would be the dependent variable?
Mrrafil [7]

Answer:

Number of absent affects the grade  

 Explanation:

the dependent variable is the grade and the independent variable is the number of absent, since the grade depends of the number of absents.

8 0
3 years ago
Design a modified priority encoder that receives an 8-bit input, A7:0and produces a 3-bit output, Y2:0. Y indicates the most sig
cupoosta [38]

Answer:

Explanation:

The first image that I attached to this solution is the diagram of a truth table for an 8 to 3 bit encoder.

The second image  gives a sketch of the schematic.

The Boolean expression for the priority encoder including its zero inputs is defined in the third image attached.

Below is a snippet of the code for an 8 to 3 bit Priority encoder:

library IEEE;

use IEEE.STD_LOGIC_1164.all;

entity encoder8_3 is

   port(

       din : in STD_LOGIC_VECTOR(7 downto 0);

       dout : out STD_LOGIC_VECTOR(2 downto 0)

        );

end encoder8_3;

architecture encoder8_3_arc of encoder8_3 is

begin

   dout <= "000" when (din="10000000") else

           "001" when (din="01000000") else

           "010" when (din="00100000") else

           "011" when (din="00010000") else

           "100" when (din="00001000") else

           "101" when (din="00000100") else

           "110" when (din="00000010") else

           "111";

end encoder8_3_arc;

3 0
3 years ago
If you do 200 joules of work using a force of 50 newtons, over what distance was the force applied ?
harina [27]
By using the formula for work, we can derive the force

W = Fd
F= \frac{W}{d} = \frac{200}{50} = 4 N

If you found that helpful, please rate this as "Brainiest"
5 0
3 years ago
Read 2 more answers
3. Two cyclists that are 500 m apart start biking toward each other. They bike at speeds of 6 and
Veronika [31]

Answer:

A) 50 seconds

B) 200 m

Explanation:

They are 500 metres apart.

And one of the bike loves at 6 m/s while the other loves at 4 m/s.

A) Let distance of the 6 m/s bike before they meet be x.

Thus, time = x/6

Since time = distance/speed

For the second bike at 4 m/s, his distance covered before they meet will be 500 - x

Thus, time = (500 - x)/4

Now they will meet each other at the same time. Thus;

x/6 = (500 - x)/4

Cross multiply to get;

4x = 3000 - 6x

6x + 4x = 3000

10x = 3000

x = 3000/10

x = 300 m

Thus, time will be;

t = 300/6

t = 50 seconds

B) Distance covered by the slower bike is (500 - x)

Since from a above, x = 300

Thus; distance = 500 - 300 = 200 m

4 0
3 years ago
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