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Pavel [41]
2 years ago
12

A substance of mass 200g measures 50cm*4cm*8cm. Calculate it density giving your answer in SI unit​

Physics
1 answer:
Oduvanchick [21]2 years ago
5 0

Answer:

0.2kg/0.0016m^3

Explanation:

200g is 0.2 kg

50*4*8 is equivalent to 1600 cubic centimeters which is also equivalent to 0.0016 cubic meters.

The SI unit for density is kg per cubic meter

So now we have 0.2kg/0.0016m^3

I hoped this helped, and if it did please give me brainliest

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If a woman weighs 125 lb, her mass expressed in kilograms is x kg, where x is
adelina 88 [10]
The first thing you should know to solve this problem is the conversion of pounds to kilograms:
 1lb = 0.45 Kg
 We can solve this problem by a simple rule of three
 1lb ---> 0.45Kg
 125lb ---> x
 Clearing x we have:
 x = ((125) / (1)) * (0.45) = 56.25 Kg.
 Answer
 her mass expressed in kilograms is 56.25 Kg.
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2 years ago
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About how many days in the moon’s cycle is it waxing?.
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Answer: 29.5 days

The waxing moon phase comprises three separate moon phases: the Waxing Crescent, First Quarter, and the Waxing Gibbous.

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2 years ago
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A toy rocket, launched from the ground, rises vertically with an acceleration of 28 m/s 2 for 9.7 s until its motor stops. Disre
vredina [299]

Answer:

5080.86m

Explanation:

We will divide the problem in parts 1 and 2, and write the equation of accelerated motion with those numbers, taking the upwards direction as positive. For the first part, we have:

y_1=y_{01}+v_{01}t+\frac{a_1t^2}{2}

v_1=v_{01}+a_1t

We must consider that it's launched from the ground (y_{01}=0m) and from rest (v_{01}=0m/s), with an upwards acceleration a_{1}=28m/s^2 that lasts a time t=9.7s.

We calculate then the height achieved in part 1:

y_1=(0m)+(0m/s)t+\frac{(28m/s^2)(9.7s)^2}{2}=1317.26m

And the velocity achieved in part 1:

v_1=(0m/s)+(28m/s^2)(9.7s)=271.6m/s

We do the same for part 2, but now we must consider that the initial height is the one achieved in part 1 (y_{02}=1317.26m) and its initial velocity is the one achieved in part 1 (v_{02}=271.6m/s), now in free fall, which means with a downwards acceleration a_{2}=-9,8m/s^2. For the data we have it's faster to use the formula v_f^2=v_0^2+2ad, where d will be the displacement, or difference between maximum height and starting height of part 2, and the final velocity at maximum height we know must be 0m/s, so we have:

v_{02}^2+2a_2(y_2-y_{02})=v_2^2=0m/s

Then, to get y_2, we do:

2a_2(y_2-y_{02})=-v_{02}^2

y_2-y_{02}=-\frac{v_{02}^2}{2a_2}

y_2=y_{02}-\frac{v_{02}^2}{2a_2}

And we substitute the values:

y_2=y_{02}-\frac{v_{02}^2}{2a_2}=(1317.26m)-\frac{(271.6m/s)^2}{2(-9.8m/s^2)}=5080.86m

3 0
3 years ago
If you increase the length ? of a pendulum by a factor of 9, how will the period t increase?
garik1379 [7]
T = 2 * pie √(L/g)

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hope it helped :)
3 0
3 years ago
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An astronaut lands on an alien planet. He places a pendulum (L = 0.200 m) on the surface and sets it in simple harmonic motion,
Ne4ueva [31]
A)  f = 1.8 rev/s = 2 Hz 
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B)  not really sure..srry

C)  </span><span>T = 2 pi √ ( L / g ) </span>
<span>0.57 = 2 x 3.14 x √ ( 0.2 / g )
</span><span>
g = 25.5 m/s²
</span>
Hope this helps a little at least.. :)

5 0
3 years ago
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