Answer is: glycerol because it is more viscous and has a larger molar mass.
Viscosity depends on intermolecular interactions.
The predominant intermolecular force in water and glycerol is hydrogen bonding.
Hydrogen bond is an electrostatic attraction between two polar groups in which one group has hydrogen atom (H) and another group has highly electronegative atom such as nitrogen (like in this molecule), oxygen (O) or fluorine (F).
In 6.23 * 10^23 atoms, number of moles = 1
So, It would be: 3.94 * 10^23 / 6.23 * 10^23
= 0.654 moles
In short, Your Answer would be Option A
Hope this helps!
The deltaHrxn = -243 kJ/mol the deltaHrxn of CH4(methane) = -802 kJ/mol
The fuel that yields more energy per mole is METHANE. The negative sign merely signifies the release of energy. Thus, 802 kJ/mol is greater than 243 kJ/mol.
The fuel that yields more energy per gram is HYDROGEN. Here is the computation:
deltaHrxn = (-243 kJ/mol)(1 mol/2.016 g H2) <span>= -120.535714286 kJ/g or -121 kJ/g
</span>deltaHrxn of CH4(methane) = (-802 kJ/mol)(1 mol/16.04 g)
<span>= -50 kJ/g
</span>
As discussed the negative sign serves as the symbol of released energy. Thus, 121 is greater than 50.
Image #1 is clearly sharing their electrons to complete an octet, which makes me believe it is a Double Bond.
Image #2 is a duplicate (if my computer is displaying this picture correctly) which if this is the case and my computer isn't the issue I'd say it is a Double Bond. I don't think "above" and "below" make a difference but it may depend on the attachments and where they were originally placed. Either way Image #1 and #2 are Double Bonds.
Image #3 if I recall accurately is where 4 valence electrons must be gained. I'm a bit fuzzy with valence electrons and recommended viewing Crash Course on this if you'd like to perfect your understanding on Valence Electrons, but I recall a similar question and I remember 4 valence electrons for this type of image. Wish I could help more on this. :(