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Alex777 [14]
3 years ago
14

A sample of oxide iron weighing 2.40g was heated in a stream of hydrogen until it was completely converted to the metal. If the

metal weighed 1.68g. What is the formula of the iron oxide? (Fe=56, O=16)
Chemistry
1 answer:
wlad13 [49]3 years ago
4 0

Answer:

Fe₂O₃

Explanation:

To solve this question we must find the moles of Iron in 1.68g. With the difference of the masses we can find the moles of oxygen. The formula will be obtained with the ratio of both amount of moles:

<em>Moles Fe:</em>

1.68g * (1mol / 56g)  =0.03moles

<em>Moles O:</em>

2.40g-1.68g = 0.72g * (1mol/16g) = 0.045moles

The ratio O/Fe is:

0.045moles / 0.03moles = 1.5 moles. this ratio is obtained if the formula is:

<h3>Fe₂O₃</h3>
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What is the mass of H2O produced when 14.0 grams of H2 reacts completely with 2.0 grams of O2?
Vladimir79 [104]
Balanced chemical equation:

2 H2 + 1 O2 = 2 H2O

4 g H2  -------> 32 g O2 -----------> 36 g H2O
   ↓                       ↓                             ↓
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32 * mass H2O = 2.0 * 36

32 * mass H2O = 72

mass of H2O = 72 / 32

mass of H2O = 2.25 g

hope this helps!.


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