It will be Oxygen . And total 8 protons, 8 electrons and 9 neutrons are present in it.
<u>Given:</u>
Initial concentration of potassium iodate (KIO3) M1 = 0.31 M
Initial volume of KIO3 (stock solution) V1 = 10 ml
Final volume of KIO3 V2 = 100 ml
<u>To determine:</u>
The final concentration of KIO3 i.e. M2
<u>Explanation:</u>
Use the relation-
M1V1 = M2V2
M2 = M1V1/V2 = 0.31 M * 10 ml/100 ml = 0.031 M
Ans: The concentration of KIO3 after dilution is 0.031 M
I believe the answer is option B. The bonded pair of valence electrons are shown using circles
<span>31.9 grams butane needed to produce 96.7 grams CO2
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