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2 years ago

(100 points) Atleast 5 slogans on saving fuel.

Chemistry

2 answers:

Tcecarenko [31]2 years ago

7 0

Hope That Helps!!!

Explanation:

Here are Best Slogans on Save Fuel.

-Towards a better future.

-Save to sustain.

-Save fuel for a better world.

-Make sure to keep some for the next generation.

-Our resources are limited.

-Save to expand.

-Saving fuel has no alternatives.

-Save money while saving fuels.

Inessa05 [86]2 years ago

6 0

Answer:

Save Fuel, Save Earth

Fuel and time wait for none!

Be wise, don’t waste fuel

Save fuel, stop being cruel

Don’t contribute towards global warming

Care for future, save fuel

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A gas evolved during the fermentation of sugar was collected at 22.5°C and 702 mmHg. After purification its volume was found to

miskamm [114]

Answer:

A) 0.95 mol

Explanation:

We will assume the gas given off in the fermentation is an ideal gas because that allows us to use the ideal gas equation.

PV = nRT

First let's convert all measurements to units that we can use

P = 702 mmHg * 1 atm/760 mmHg = 0.92368 atm

V = 25.0 L

R = 0.08206 L-atm/mol-K

T = 22.5 °C +273.15 = 295.65 K

PV = nRT

0.92368 atm * 25.0 L = n * 0.08206 L-atm/mol-K * 295.65 K

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2 years ago

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2 years ago

Is aluminum foil a mixture or a pure substance?

Naddik [55]

Pure Substance.........

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2 years ago

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Charra [1.4K]

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2 years ago

Start with 100.00 mL of 0.10 M acetic acid, CH3COOH. The solution has a pH of 2.87 at 25 oC. a) Calculate the Ka of acetic acid

jasenka [17]

Answer: a) The $K_a$ of acetic acid at $25^0C$ is $1.82\times 10^{-5}$

b) The percent dissociation for the solution is $4.27\times 10^{-3}$

Explanation:

$CH_3COOH\rightarrow CH_3COO^-H^+$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.10 M and $\alpha$ = ?

Also $pH=-log[H^+]$

$2.87=-log[H^+]$

$[H^+]=1.35\times 10^{-3}M$

$[CH_3COO^-]=1.35\times 10^{-3}M$

$[CH_3COOH]=(0.10M-1.35\times 10^{-3}=0.09806M$

Putting in the values we get:

$K_a=\frac{(1.35\times 10^{-3})^2}{(0.09806)}$

$K_a=1.82\times 10^{-5}$

b) $\alpha=\sqrt\frac{K_a}{c}$

$\alpha=\sqrt\frac{1.82\times 10^{-5}}{0.10}$

$\alpha=4.27\times 10^{-5}$

$\% \alpha=4.27\times 10^{-5}\times 100=4.27\times 10^{-3}$

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3 years ago