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Naily [24]
3 years ago
11

The potential energy stored in the compressed spring of a dart gun, with a spring constant of 31.50 N/m, is 1.240 J. Find by how

much is the spring is compressed.
Physics
1 answer:
Ber [7]3 years ago
8 0

Answer:

0.281  m

Explanation:

Applying,

W = 0.5ke².................. Equation 1

Where W = Workdone by the stretched spring, k = spring constant, e = extension/ compression of the spring

make e the subject of the equation

e = √(2W/k)................ Equation 2

From the question,

Given: W = 1.240J, k = 31.50 N/m

Substitute these values into equation 2

e = √(2×1.240/31.50)

e = √(0.07873)

e = 0.281  m

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Answer:

i) 24.5 m/s

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Explanation:

Desde una altura de 120 m se deja caer un cuerpo. Calcule a 2.5 s i) la velocidad que toma; ii) cuánto ha disminuido; iii) cuánto queda por hacer

i) Los parámetros dados son;

Altura inicial, s = 120 m

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De la ecuación de caída libre, tenemos;

v = u + gt

Dónde:

u = Velocidad inicial = 0 m / s

g = Aceleración debida a la gravedad = 9.81 m / s²

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Por lo tanto;

v = 0 + 9.8 × 2.5 = 24.5 m / s

ii) El nivel que el cuerpo ha alcanzado en 2.5 segundos está dado por la relación

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As a pendulum swings from its highest to lowest position, what happens to its kinetic and potential energy?
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Electric potential energy is given by

U=k\dfrac{q^2}{d}

In this system with three charges which are equidistant from each other

U=k\dfrac{q^2}{d}+k\dfrac{q^2}{d}+k\dfrac{q^2}{d}

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