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Naily [24]
3 years ago
11

The potential energy stored in the compressed spring of a dart gun, with a spring constant of 31.50 N/m, is 1.240 J. Find by how

much is the spring is compressed.
Physics
1 answer:
Ber [7]3 years ago
8 0

Answer:

0.281  m

Explanation:

Applying,

W = 0.5ke².................. Equation 1

Where W = Workdone by the stretched spring, k = spring constant, e = extension/ compression of the spring

make e the subject of the equation

e = √(2W/k)................ Equation 2

From the question,

Given: W = 1.240J, k = 31.50 N/m

Substitute these values into equation 2

e = √(2×1.240/31.50)

e = √(0.07873)

e = 0.281  m

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4 0
3 years ago
Y=mx+b if y=8.18 m=1.31 b=17.2 then find x
Dafna1 [17]

Plug in the corresponding values into y = mx + b

8.18 in for y

1.31 in for m

17.2 in for b

8.18 = 1.31x + 17.2

Now bring 17.2 to the left side by subtracting 17.2 to both sides (what you do on one side you must do to the other). Since 17.2 is being added on the right side, subtraction (the opposite of addition) will cancel it out (make it zero) from the right side and bring it over to the left side.

8.18 - 17.2 = 1.31x

-9.02 = 1.31x

Then divide 1.31 to both sides to isolate x. Since 1.31 is being multiplied by x, division (the opposite of multiplication) will cancel 1.31 out (in this case it will make 1.31 one) from the right side and bring it over to the left side.

-9.02/1.31 = 1.31x/1.31

x ≈ -6.8855

x is roughly -6.89

Hope this helped!

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8 0
4 years ago
Read 2 more answers
Jonathan must lift a 3000n rock using a lever. jonathan uses 300n of force to push down on the lever to move the rock. what is t
-Dominant- [34]
The load is the weight of the rock that Jonathan lifts:
L=3000 N
The effort instead is the force applied in input to the lever in order to lift the rock:
E=300 N

So, the ratio between load and effort for this exercise is
\frac{L}{E}= \frac{3000 N}{300 N}=10
So, the ratio is 10:1.
3 0
3 years ago
A skier starts from rest down a slope 500.0 M long, the skier accelerates at a constant rate of 2.00 m/s/s, what's the velocity
nevsk [136]
We can use the kinematic equation
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where Vf is what we are looking for
Vi is 0 since we start from rest
a is acceleration
and d is the distance

we get
(Vf)^2 = (0)^2 + 2*(2)*(500)
(Vf)^2 = 2000
Vf = about 44.721
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8 0
3 years ago
What is the distance between two spheres (20 kg and 30 kg) attracted by a force of 2 x 10^-5 Newtons.
creativ13 [48]
2 times 10 to the power of 5 is your answer.
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4 years ago
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