Question

The potential energy stored in the compressed spring of a dart gun, with a spring constant of 31.50 N/m, is 1.240 J. Find by how much is the spring is compressed.

Answer 1

Answer:

0.281  m

Explanation:

Applying,

W = 0.5ke².................. Equation 1

Where W = Workdone by the stretched spring, k = spring constant, e = extension/ compression of the spring

make e the subject of the equation

e = √(2W/k)................ Equation 2

From the question,

Given: W = 1.240J, k = 31.50 N/m

Substitute these values into equation 2

e = √(2×1.240/31.50)

e = √(0.07873)

e = 0.281  m