Here is a site my buddie has to help you. Well co-owner..
https://www.quora.com/Why-is-fresly-prepared-FeSO4-required-for-the-ring-test
Number 3 i think is <span>d.heat moves from an object of higher temperature to an object of lower temperature</span>
Answer:
The answer to your question is 3% H2SO4 solution
Explanation:
Data
Concentration 2 = C₂ = ?
Concentration 1 = C₁ = 15 %
Volume 1 = V₁ = 50 ml
Volume 2 = V₂ = 250 ml
Formula
C₁V₁ = C₂V₂
Solve for C₂
C₂ = C₁V₁ / V₂
Substitution
C₂ = (15)(50) / 250
Simplification and result
C₂ = 3 %
Answer:
Microliters = ![7.4\times 10^{-58}](https://tex.z-dn.net/?f=%3Cstrong%3E7.4%5Ctimes%2010%5E%7B-58%7D%3C%2Fstrong%3E)
Explanation:
SI unit of volume is liter.
..............................(1)
1dm=10cm
.................(2)
replacing value of
from equation (1) in equation (2)
...................(3)
but
....................(4)
replacing value of 1 liter from equation (3) in equation (4)
![1000 cm^{3} = 10^{6} microliters](https://tex.z-dn.net/?f=%3Cstrong%3E1000%20cm%5E%7B3%7D%20%3D%2010%5E%7B6%7D%20microliters%3C%2Fstrong%3E)
on solving further ,we get
![1 cm^{3} = \frac{10^{6}}{10^{3}}microliter](https://tex.z-dn.net/?f=%3Cstrong%3E1%20cm%5E%7B3%7D%20%3D%20%5Cfrac%7B10%5E%7B6%7D%7D%7B10%5E%7B3%7D%7Dmicroliter%3C%2Fstrong%3E)
![1 cm^{3} = 1000 microliter](https://tex.z-dn.net/?f=%3Cstrong%3E1%20cm%5E%7B3%7D%20%3D%201000%20microliter%3C%2Fstrong%3E)
![7.4\times 10^{-61}\times 1000](https://tex.z-dn.net/?f=%3Cstrong%3E7.4%5Ctimes%2010%5E%7B-61%7D%5Ctimes%201000%3C%2Fstrong%3E)
Microliters = ![7.4\times 10^{-58}](https://tex.z-dn.net/?f=%3Cstrong%3E7.4%5Ctimes%2010%5E%7B-58%7D%3C%2Fstrong%3E)
Answer:
6750 J
Explanation:
The specific heat capacity of iron is 450 J/kg/K
Quantity of heat = mcθ; where m is the mass and c is the specific heat capacity and θ is the temperature change.
Therefore;
m = 3 kg, c = 450 J/kg/K and θ = 5°C
Quantity of heat = 3 × 450 × 5
<u>= 6150 Joules</u>