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3 years ago

12

Convert 14 minutes to seconds. (What unit do we want) 1. Seconds 2. Minutes

1 answer:

Mnenie [13.5K]3 years ago

4 0

Answer:

Seconds...

Explanation:

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A comet is cruising through the solar system at a speed of 50,000 kilometers per hour foe 4 hours time. What is the total distan

Triss [41]

Answer:

<em>The distance covered by comet is </em> $200,000 km$

Explanation:

Speed is defined as the rate of change of distance with time. It is given by the equation speed= $\bold{\frac{distance}{time}}$

Thus distance= $speed*time$

In this problem it is given that speed of comet= $\frac{50,000km}{hr}$

time travelled by the comet= 4 hours

Thus distance= $speed*time$

= $500000*4$

= $\bold{200,000km}$

5 0

2 years ago

Two boxes are at rest on a smooth, horizontal surface. The boxes are in contact with one another. If box 1 is pushed with a forc

Maslowich

Answer:

mass of box 1 = 2.20 kg

mass of box 2 = 5.93 kg

Explanation:

Let the mass of box 1 and box 2 is respectively

$m_1$ and $m_2$

so we will have

Force applied on box 1 then acceleration

$a = \frac{F}{m_1 + m_2}$

$1.50 = \frac{12.2}{m_1 + m_2}$

$m_1 + m_2 = 8.13$

Now we know that contact force between them in above case is given as

$F_n = m_2a$

$8.90 = m_2(1.5)$

$m_2 = 5.93 kg$

now we have

$m_1 = 2.20 kg$

8 0

3 years ago

A neutron consists of one "up" quark of charge +2e/3 and two "down" quarks each having charge -e/3. If we assume that the down q

Anon25 [30]

Answer:

The magnitude of the electrostatic force is 120.85 N

Explanation:

We can use Coulomb's law to find the electrostatic force between the down quarks.

In scalar form, Coulomb's law states that for charges $q_1$ and $q_2$ separated by a distance d, the magnitude of the electrostatic force F between them is:

$F = k \frac{|q_1q_2|}{d^2}$

where $k$ is Coulomb's constant.

Taking the values:

$d = 4.6 \ 10^{-15} m$

$q_1 = q_2 = - \frac{e}{3} = - \frac{1.6 \ 10^{-19} \ C}{3}$

and knowing the value of the Coulomb's constant:

$k = 8.99 \ 10 ^{9} \frac{N m^2}{C^2}$

Taking all this in consideration:

$F = 8.99 \ 10 ^{9} \frac{N m^2}{C^2} \frac{ (- \frac{1.6 \ 10^{-19} \ C}{3} ) ^2}{(4.6 \ 10^{-15} m)^2}$

$F = 120.85 \ N$

8 0

3 years ago

A student is standing 8 m from a roaring truck engine that is measured at 20 dB. The student moves 4 m closer to

Ipatiy [6.2K]

Answer:80 dB

Explanation:

5 0

3 years ago

To the nearest square foot, how many square feet are there in an area of 4.4 square meters?

vichka [17]

Answer:

4.4 square meters = 47 square foot

Explanation:

We have

1 meter = 3.28084 foot

1 square meter = 3.28084 x 3.28084 square foot = 10.76 square foot

4.4 square meters = 4.4 x 10.76 = 47.36 square foot = 47 square foot

4.4 square meters = 47 square foot

3 0

3 years ago