Answer:
t = 4.08 s
R = 40.8 m
Explanation:
The question is asking us to solve for the time of flight and the range of the rock.
Let's start by finding the total time it takes for the rock to land on the ground. We can use this constant acceleration kinematic equation to solve for the displacement in the y-direction:
We have these known variables:
- (v_0)_y = 0 m/s
- a_y = -9.8 m/s²
- Δx_y = -20 m
And we are trying to solve for t (time). Therefore, we can plug these values into the equation and solve for t.
- -20 = 0t + 1/2(-9.8)t²
- -20 = 1/2(-9.8)t²
- -20 = -4.9t²
- t = 4.08 sec
The time it takes for the rock to reach the ground is 4.08 seconds.
Now we can use this time in order to solve for the displacement in the x-direction. We will be using the same equation, but this time it will be in terms of the x-direction.
List out known variables:
- v_0 = 10 m/s
- t = 4.08 s
- a_x = 0 m/s
We are trying to solve for:
By using the same equation, we can plug these known values into it and solve for Δx.
- Δx = 10 * 4.08 + 1/2(0)(4.08)²
- Δx = 10 * 4.08
- Δx = 40.8 m
The rock lands 40.8 m from the base of the cliff.
We can use the formula of the moment of inertia given by:
![r\cdot F=I\alpha](https://tex.z-dn.net/?f=r%5Ccdot%20F%3DI%5Calpha)
Where:
r = Distance from the point about which the torque is being measured to the point where the force is applied
F = Force
I = Moment of inertia
α = Angular acceleration
So:
![\begin{gathered} r\cdot F=(-0.26\times314+290\times0.32)=92.8-81.64=11.16 \\ I=0.930 \\ so,_{\text{ }}solve_{\text{ }}for_{\text{ }}\alpha: \\ \alpha=\frac{r\cdot F}{I} \\ \alpha=\frac{11.16}{0.930} \\ \alpha=\frac{12rad}{s^2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20r%5Ccdot%20F%3D%28-0.26%5Ctimes314%2B290%5Ctimes0.32%29%3D92.8-81.64%3D11.16%20%5C%5C%20I%3D0.930%20%5C%5C%20so%2C_%7B%5Ctext%7B%20%7D%7Dsolve_%7B%5Ctext%7B%20%7D%7Dfor_%7B%5Ctext%7B%20%7D%7D%5Calpha%3A%20%5C%5C%20%5Calpha%3D%5Cfrac%7Br%5Ccdot%20F%7D%7BI%7D%20%5C%5C%20%5Calpha%3D%5Cfrac%7B11.16%7D%7B0.930%7D%20%5C%5C%20%5Calpha%3D%5Cfrac%7B12rad%7D%7Bs%5E2%7D%20%5Cend%7Bgathered%7D)
Answer:
12 rad/s²
Answer:
(A) She needs to move the decimal point by 3 places
Hi there!
Great question!
Basketballs have air inside them. A special pump is used to insert the air. That's why you can lift the basketballs off the ground easily. If it was a solid, though, you'd hardly be able to lift the ball up! Basketballs can float, too, because anything with air inside can float. If it were solid, it would sink in the water easily.
Hope this helps! :D
It’s true, because it also depends on things like mass. Higher temperature but less mass< Lower temperature but more mass.