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3 years ago

How do renewable and nonrenewable resources differ?

Physics

2 answers:

Free_Kalibri [48]3 years ago

5 0

Answer:

The third one is true.

Explanation:

Renewable resources replenish within our lifetime.

Afina-wow [57]3 years ago

4 0

Answer:

Explanation:

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What do you notice about the angle of earth?

Butoxors [25]

Answer:

Explanation:

Instead, Earth has seasons because our planet's axis of rotation is tilted at an angle of 23.5 degrees relative to our orbital plane, that is, the plane of Earth's orbit around the sun. The tilt in the axis of the Earth is called its obliquity by scientists. ... Over the course of a year, the angle of tilt does not vary

7 0

3 years ago

Read 2 more answers

What is the moment of inertia of the object starting from rest if it has a final velocity of 5.9 m/s? Express the moment of iner

Bogdan [553]

Answer:

The moment of inertia is I = 0.126*R^2*M

Explanation:

We can calculate the moment of inertia of an object that starts from rest and has a final velocity using the energy conservation equation, as follows:

Ek1 + Ep1 = Ek2 + Ep2, where

Ek1 = kinetic energy of the object before to roll down

Ep1 = potential energy of the object

Ek2 = kinetic energy when the object comes down

Ep2 = potential energy of the object at the bottom

We have the follow:

Ek1 = 0

Ep1 = M*g*h

Ek2 = ((I*w)/2) + ((M*v^2)/2)

Ep2 = 0

Replacing values:

0 + M*g*h = ((I*w)/2) + ((M*v^2)/2) + 0

where:

M = mass of the object

g = gravitational acceleration

I = moment of the inertia

w = angular velocity = v/R

h = height

M*g*h = ((1/2) * I * (v^2/R^2)) + ((M*v^2)/2)

M*9.8*2 = (I*(5.9^2)/(2*R^2)) + ((5.9^2 * M)/2)

19.6 * M = ((17.4*I)/R^2) + 17.4*M

Clearing I, we have:

I = 0.126*R^2*M

5 0

3 years ago

The Difference between two opposing forces is called _____ force

Galina-37 [17]

Answer:

Unbalance force

Explanation:

Unbalanced force creates a difference between two force moving in opposite direction. some of the causes of the unbalance forces is friction amd air drags

5 0

3 years ago

Read 2 more answers

Your car is initially at rest when your hit that gas and the car begins to accelerate at a rate of 2.857 m/s/s. The acceleration

Maru [420]

Given parameters:

Initial velocity = 0m/s

Acceleration = 2.857m/s²

Time = 15.5s

Unknown:

Final speed of the car = ?

Solution:

We use one of the motion equations to solve this problem;

V = U + at

Where V is the final velocity

U is the initial velocity

a is the acceleration

t is the time taken

V = 0 + 2.857 x 15.5 = 44.28m/s

6 0

4 years ago

A 50kg boy stands on rough horizontal ground. The coefficient

prisoha [69]

Given :

A 50 kg boy stands on rough horizontal ground. The coefficient of static friction, us, is 0.68.

To Find :

The maximum static friction between the boy and the ground is _ N.

Solution :

We know maximum static friction is given by :

$F = \mu mg \\\\F= 0.68\times 50\times 9.8\\\\F = 333.2\ N$

Therefore, maximum static friction is 333.2 N.

Hence, this is the required solution.

8 0

3 years ago