Answer:
Most of free energy available from oxidation of the glucose remains in pyruvate.
Explanation:
The overall reaction of the process glycolysis is:
Glucose + 2 NAD⁺ + 2 ADP + 2 Pi ⇒ 2 Pyruvate + 2 NADH + 2 H⁺ + 2ATP
Glucose is oxidized to give 2 molecules of pyruvate and 2 molecules of NADH and ATP (Energy currency).
<u>Though the free energy of oxidation of glucose is high but only 2 NADH is formed because the most of the free energy that is being released from the oxidation of glucose remains in the pyruvate which is produced in the reaction and thus only 2 molecules are formed.</u>
From Melting! Hope this helped
Answer:
Law of cross-cutting relationships
Explanation:
This interpretation is based on the law of cross - cutting relationships.
This law states that "faults and fractures that cuts through a rock are younger than the rocks they cut through".
- In a sequence of strata, the strata that are not cut through by these features are younger than the cross -cutting features.
- The igneous intrusion is younger since it cuts through the rock layers.
Answer:
Final concentration of C at the end of the interval of 3s if its initial concentration was 3.0 M, is 3.06 M and if the initial concentration was 3.960 M, the concentration at the end of the interval is 4.02 M
Explanation:
4A + 3B ------> C + 2D
In the 3s interval, the rate of change of the reactant A is given as -0.08 M/s
The amount of A that has reacted at the end of 3 seconds will be
0.08 × 3 = 0.24 M
Assuming the volume of reacting vessel is constant, we can use number of moles and concentration in mol/L interchangeably in the stoichiometric balance.
From the chemical reaction,
4 moles of A gives 1 mole of C
0.24 M of reacted A will form (0.24 × 1)/4 M of C
Amount of C formed at the end of the 3s interval = 0.06 M
If the initial concentration of C was 3 M, the new concentration of C would be (3 + 0.06) = 3.06 M.
If the initial concentration of C was 3.96 M, the new concentration of C would be (3.96 + 0.06) = 4.02 M
Answer:
2.44 K IS THE TEMPERATURE OF THE GAS
Explanation:
PV = nRT
P = 0.5 atm
V = 2 L
n = 5 moles
R = 0.082 L atm mol^-1 K^-1
T = ?
Substituting for T in the equation, we obtain:
T = P V / nR
T = 0.5 * 2 / 5 * 0.082
T = 1 / 0.41
T = 2.44 K
The temperature of the gas is 2.44 K
