Explanation:
It is given that,
Voltage of the battery, V = 12 V
Current, I = 100 ampere-hours
Energy stored is given by the product of power and time taken. So,
![E=P\times t](https://tex.z-dn.net/?f=E%3DP%5Ctimes%20t)
P is the power, ![P=V\times I](https://tex.z-dn.net/?f=P%3DV%5Ctimes%20I)
![P=12\times 100](https://tex.z-dn.net/?f=P%3D12%5Ctimes%20100)
P = 1200 watts
This power can be used for 1 hour or 3600 seconds
Energy, ![E=1200\times 3600](https://tex.z-dn.net/?f=E%3D1200%5Ctimes%203600)
E = 4320000 J
So, the energy stored in this battery is 4320000 J. Hence, this is the required solution.
A sample of nitrogen gas has a volume of 5.0 ml at a pressure of 1.50 atm. what is the pressure exerted by the gas if the volume increases to 30.0 ml, at constant temperature is 0.25atm.
On constant temperature, the pressure and volume relation become constant before and after the change in quantitities have occurred.
According to Boyle's Law,
P₁V₁ = P₂V₂
where, P₁ is pressure exerted by the gas initially
V₁ is the volume of gas initially
P₂ is pressure exerted by the gas finally
V₂ is the volume of gas finally
Given,
P₁ = 1.5 atm
V₁ = 5 ml
V₂ = 30 ml
P₂ =?
On substituting the given values in the above equation:
P₁V₁ = P₂V₂
1.5 atm × 5 ml = P₂ × 30 ml
P₂ = 0.25 atm
Hence, pressure exerted by the gas is 0.25atm.
Learn more about Boyle's Law here, brainly.com/question/1437490
#SPJ4
D=m÷v
so density would be 57.9 ÷ 3 = 19.3 g/cm³
Answer:
1/2
Explanation:
The energy stored in a capacitor is given by
![U=\frac{1}{2}CV^2](https://tex.z-dn.net/?f=U%3D%5Cfrac%7B1%7D%7B2%7DCV%5E2)
where
C is the capacitance
V is the potential difference
Calling
the capacitance of capacitor 1 and
its potential difference, the energy stored in capacitor 1 is
![U=\frac{1}{2}C_1 V_1^2](https://tex.z-dn.net/?f=U%3D%5Cfrac%7B1%7D%7B2%7DC_1%20V_1%5E2)
For capacitor 2, we have:
- The capacitance is half that of capacitor 1: ![C_2 = \frac{C_1}{2}](https://tex.z-dn.net/?f=C_2%20%3D%20%5Cfrac%7BC_1%7D%7B2%7D)
- The voltage is twice the voltage of capacitor 1: ![V_2 = 2 V_1](https://tex.z-dn.net/?f=V_2%20%3D%202%20V_1)
so the energy stored in capacitor 2 is
![U_2 = \frac{1}{2}C_2 V_2^2 = \frac{1}{2}\frac{C_1}{2}(2V_1)^2 = C_1 V_1^2](https://tex.z-dn.net/?f=U_2%20%3D%20%5Cfrac%7B1%7D%7B2%7DC_2%20V_2%5E2%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7BC_1%7D%7B2%7D%282V_1%29%5E2%20%3D%20C_1%20V_1%5E2)
So the ratio between the two energies is
![\frac{U_1}{U_2}=\frac{\frac{1}{2}C_1 V_1^2}{C_1 V_1^2}=\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7BU_1%7D%7BU_2%7D%3D%5Cfrac%7B%5Cfrac%7B1%7D%7B2%7DC_1%20V_1%5E2%7D%7BC_1%20V_1%5E2%7D%3D%5Cfrac%7B1%7D%7B2%7D)
Explanation:
Mirrors consist of reflecting surfaces that reflect light.
Reflection is a phenomenon of light wave (but also of other types of waves) in which a ray of light hits a surface, and then it bounces back into the original medium at a certain angle.
The direction of the reflected ray is determined by the law of reflection:
- The incident ray, the reflected ray and the normal to the surface all lie in the same plane
- The angle of reflection is equal to the angle of incidence (where both angles are measured between the ray and the normal to the surface)
A plane mirror is a type of mirror consisting of a straight surface. As a result, light incident perpendicular to the surface is reflected back exactly in the opposite direction.
The image formed by a plane mirror is:
- The same size as the object
- Virtual (it is located behind the mirror)
- Laterally inverted
- Upright