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Ilya [14]
2 years ago
11

PLEASE HELP ASAP!!!!!! The rings of Saturn consists of particles of

Chemistry
2 answers:
zaharov [31]2 years ago
8 0

Answer:

ice

Explanation:

its ice ice ice ice ice ice

Igoryamba2 years ago
5 0
Ice Ice Baby. Ask but it is ice!
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Which statement is true about the electrons in each polar bond of a water molecule?
Greeley [361]

They are more attracted by the oxygen atom than by the hydrogen atom.

Explanation:

In the polar bond of water which is made up of hydrogen and oxygen atoms, the shared electrons are more attracted by the oxygen atom than by the hydrogen atom.  

The interatomic bond in water is a polar covalent bond.  

In this bond type, two species shares their valence electrons.  

The bond usually occurs between non-metals with an electronegativity difference that is small.

Oxygen is more electronegative compared to hydrogen.

  • This implies that oxygen pulls the electron more closely to itself since it has a greater affinity.
  • This leaves a partial negative charge on oxygen and a positive charge on hydrogen.
  • The molecule is said to be polar covalent.

learn more:

Covalent bond brainly.com/question/5258547

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3 years ago
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Self meditating to deal with stress
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I think the answer is C but I also feel it should be A...... but I think its C

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3 years ago
Find value of x<br>(6xx) + (7x100-3<br>6<br>6.94<br>100<br>100​
Alla [95]

Answer:

The annswer is 6.94

Explanation:

The answer is 6.94

5 0
3 years ago
What is the percent of oxygen in H2O2?
Effectus [21]

Answer:

94%

Explanation:

Good Luck!

7 0
3 years ago
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Consider the following reaction: NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2 How many g of CO2 would be produced from the complete r
Alenkasestr [34]
<h2>1.25 g of CO_2 would be produced from the complete reaction of 25 mL of 0.833 mol/L HC_3H_3O_2 with excess NaHCO_3 </h2>

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}    

0.833M=\frac{\text{Moles of} HC_3H_3O_2\times 1000}{25ml}\\\\\text{Moles of} HC_3H_3O_2 =\frac{0.833mol/L\times 25}{1000}=0.0208mol

NaHCO_3+HC_2H_3O_2\rightarrow NaC_2H_3O_2+H_2O+CO_2

According to stoichiometry:

1 mole of HC_2H_3O_2 will give = 1 mole of CO_2

0.0208 moles of HC_2H_3O_2 will give =\frac{1}{1}\times 0.0208=0.0208 moles of CO_2

Mass of HC_2H_3O_2=moles\times {\text {molar mass}}=0.0208\times 60g/mol=1.25g

Thus 1.25 g of CO_2 would be produced from the complete reaction of 25 mL of 0.833 mol/L HC_3H_3O_2 with excess NaHCO_3

Learn more about molarity

https://brainly.in/question/13034158

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3 years ago
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