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Airida [17]
3 years ago
15

- The Grayprational Forcewith which the earth aractsа,​

Physics
1 answer:
Fudgin [204]3 years ago
5 0

Answer:

gravitational?

Explanation:

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A concave mirror brings the sun's rays to a focus in front of the mirror. Suppose the mirror is submerged in a swimming pool but
Karo-lina-s [1.5K]

Answer:

The sun rays will be focused at the same distance from the mirror.

Explanation:

Laws of reflection do not depend on the refractive index n any form. Hence, the sun’s rays will be focused the same distance from the mirror.

8 0
3 years ago
Which is the momentum of a 100 kilogram boulder rolling south down a hill at a velocity of 5 meters per second
adell [148]
P = m * v
P = 100 * 5 Kg-m/s towards south
P = 500 Kg-m/s towards south

In short, your answer would be 500 Kg-m/s towards south

Hope this helps!
6 0
3 years ago
You kick a soccer ball of mass 0.41 kg. the ball leaves your foot with an initial speed of 23 m/s. (a what is the magnitude of t
svetoff [14.1K]
Impulse describes the change of momentum. Since we don't know the momentum of the soccer ball before the hit, this question is hard to answer. If you assume the momentum of the ball before the hit was p = 0, then the change in momentum is just Δp = Impulse = mv.
7 0
3 years ago
Read 2 more answers
Two people are talking at a distance of 3.0 m from where you are and you measure the sound intensity as 1.1 × 10-7 W/m2. Another
Tanya [424]

Answer:I_2=0.618\times 10^{-7} W/m^2

Explanation:

Given

Distance between source and  receiver d_1=3 m

Sound Intensity I_1=1.1\times 10^{-7} W/m^2

Distance of of second observer d_2=4 m

Intensity varies as

I\propto \frac{1}{d^2}

using this

I=\frac{k}{d^2}

\frac{I_1}{I_2}=\frac{d_2^2}{d_1^2}

\frac{1.1\times 10^{-7}}{I_2}=\frac{4^2}{3^2}

I_2=0.75^2\times 1.1\times 10^{-7}

I_2=0.618\times 10^{-7} W/m^2

     

6 0
3 years ago
If a capacitor has opposite 4.9 μc charges on the plates, and an electric field of 1.6 kv/mm is desired between the plates, what
Temka [501]
Q = 4.6E-6 C 
<span>E = 2.6 kV/mm = 2600 kV/m = 2600000 V/m </span>
<span>ε = 8.85E-12 F/m </span>
<span>E = Q/Aε </span>
<span>A = Q/Eε = 4.6E-6/(2600000*8.85E-12) = 0.2 m^2</span>
3 0
4 years ago
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