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3 years ago

What compound do cells break down for energy in the process of cellular respiration?

Chemistry

1 answer:

arsen [322]3 years ago

6 0

Answer:

Glucose

Explanation:

Glucose is broken down into water and carbon dioxide.

hope this helps! :)

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The substance, __________ is always produced when an active metal reacts with water.

VladimirAG [237]

Hydrogen gas (H2) is always produced.

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3 years ago

A neutral solution has a(n) _______ amount of hydroxide ions compared to hydrogen ions.

erastovalidia [21]

The answer is 'equal'. Hydroxide ions are OH- and Hydrogen ions are H+. Have you noticed they're opposite charges? Positive + negative = neutral. That's all there is to it :)

4 0

4 years ago

Consider the elements: Na, Mg, Al, Si, P.

Olegator [25]

Answer:

The elements mentioned in the series are Na, Mg, Al, Si, and P. It can be seen that all these elements are located in the same period. The atomic number of the mentioned elements are Na-11, Mg-12, Al-13, Si-14, and P-15.

a) There will be an increase in the ionization energy with the increase in the element's atomic number across a period. More energy is needed to withdraw an electron from a completely occupied shell in comparison to an incompletely occupied shell.

The atomic number of Na is 11. When one electron is withdrawn from Na, it gets converted into the inert gas configuration of Ne. Thus, it will require more energy to withdraw the second electron from Na. Hence, Na exhibits the lowest second ionization energy.

b) Across the period, with an increase in the element's atomic number, the atomic radii reduces from left to right. Thus, P exhibits the smallest atomic radius.

c) The metallic nature of the elements reduces from left to right across a period in the periodic table. Thus, P is the least metallic element.

d) Diamagnetic signifies towards the element that exhibits pair electrons in its sub-shells. The electronic configuration of Mg is,

1s2 2s2 2p6 3s2

In Mg, no unpaired electrons are present, while all the remaining elements mentioned exhibit unpaired electrons in their valence shell. Thus, Mg is the diamagnetic element.

8 0

3 years ago

A person's temperature is 40° C. What would it be in Kelvin?

Jobisdone [24]

What do you mean.....kelvin?

3 0

3 years ago

Read 2 more answers

IV.2. The following problem considers the combustion of butane in a torch. Molecular weight of butane 58.0 g/mol. 2C4H10 + 1302

Anarel [89]

Answer:

(a) Oxygen

(b) 0.84 g

Explanation:

(a)

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Given: For butane

Given mass = 1.00 g

Molar mass of butane = 58.0 g/mol

Moles of butane = 1.00 g / 58.0 g/mol = 0.0172 moles

Given: For $O_2$

Given mass = 3.00 g

Molar mass of $O_2$ = 32.0 g/mol

Moles of $O_2$ = 3.00 g / 32.0 g/mol = 0.09375 moles

According to the given reaction:

$2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O$

2 moles of butane react with 13 moles of $O_2$

1 mole of butane react with 13/2 moles of $O_2$

0.0172 moles of butane react with (13/2)*0.0172 moles of $O_2$

Moles of $O_2$ required = 0.1118 moles

Available moles of $CuSO_4$ = 0.09375 moles

Limiting reagent is the one which is present in small amount. Thus, $O_2$ is limiting reagent. (0.09375 < 0.1118 )

(b)

The formation of the product is governed by the limiting reagent. So,

13 moles of $O_2$ react with 2 moles of butane

1 mole of $O_2$ react with 2/13 moles of butane

0.09375 mole of $O_2$ react with (2/13)*0.09375 moles of butane

Moles of butane used = 0.0144 moles

Molar mass of butane = 58.0 g/mol

Mass of butane used = Moles × Molar mass = 0.0144 × 58.0 g = 0.84 g

(c)

13 moles of $O_2$ on reaction forms 8 moles of carbon dioxide

1 mole of $O_2$ on reaction forms 8/13 moles of carbon dioxide

0.09375 mole of $O_2$ on reaction forms (8/13)*0.09375 moles of carbon dioxide

Moles of carbon dioxide obtained = 0.05769 moles

Molar mass of $CO_2$ = 44.0 g/mol

Mass of $CO_2$ = Moles × Molar mass = 0.05769 × 44.0 g = 2.54 g

6 0

3 years ago