Answer:
Curl up test.
Explanation:
The curl up test is done to check the strength of the abdomen muscles and the stability of the core muscles. The strength of the core muscles determines the stability of the body.
The curl up test is done to test the abdomen strength and endurance and the strength of the back muscles.
The test requires the following materials: A flat cushioned surface(clean) and a measuring strip
- The measuring strip is placed on the mat under the students legs so that their fingertips are just resting on the nearest edge of the measuring strip. The feet cannot be held or rest against an object. Keeping heels in contact with the mat, the student curls up slowly, sliding their fingers across the measuring strip until the fingertips reach the other side, then curls back down until their head touches the mat. There should be 20 curl-ups per minute
Answer:
no, yo no lo conosco...porque preguntas?
Explanation:
Answer:
Let the mass of the book be "m", acceleration due to gravity be "g", velocity be "v" and height be "h".
Now if we are holding a book at a certain height (h), <em><u>the potential energy will be maximum which is equal to mass× acceleration due to gravity× height (= mgh)</u>.</em>
(Remember: kinetic energy =0)
Now we consider that the book is dropped, in this case a force will act downward towards the centre of the earth, <em><u>Force= mass× acceleration due to gravity (F=mg)</u></em>. It is equal to the weight of the book.
While the book is falling, the potential energy stored in the book converts into kinetic energy and strikes the floor with <em><u>the maximum kinetic energy= (1/2)×mass×velocity² (=1/2mv²)</u>.</em>
(Remember: kinetic energy=0)
Due to this process the whole energy is conserved.
As the potential energy decreases kinetic energy increases.
Answer:
two wavelength are present
as wavelength is counted either from crest to crest or trough to trough and there are only 2
Answer:
The net acceleration of the boat is approximately 6.12 m/s² downwards
Explanation:
The buoyant or lifting force applied to the boat = 790 N
The mass of the boat lifted by the buoyant force = 214 kg
The force applied to a body is defined as the product of the mass and the acceleration of the body. Therefore, the buoyant force, F, acting on the boat can be presented as follows;
Fₐ = F - W
The weight of the boat = 214 × 9.81 = 2099.34 N
Therefore;
Fₐ = 790 - 2099.34 = -1309.34 N
Fₐ = Mass of the boat × The acceleration of the boat
Given that the buoyant force, Fₐ, is the net force acting on the boat, we have;
F = Mass of the boat × The net acceleration of the boat
F = -1309.34 N = 214 kg × The net acceleration of the boat
∴ The net acceleration of the boat = -1309.34 N/(214 kg) ≈ -6.12 m/s²
The net acceleration of the boat ≈ 6.12 m/s² downwards
