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suter [353]
3 years ago
12

Periodic waves with a wavelength of 0.50 meter move with a speed of 0.30 meter in medium A. When the waves enter medium B, they

travel at 0.15 meter per second. Calculate the wavelength of the waves in medium B.
Physics
1 answer:
iris [78.8K]3 years ago
7 0

Answer:

0.25 m

Explanation:

Refraction occurs when the velocity or wavelength of a wave changes at the interface between two media.

We know that refractive index=

Wavelength in medium A/wavelength in medium B = velocity in medium A/velocity in medium B

Let the wavelength of medium B be a

0.5/a = 0.3/0.15

0.5 × 0.15 = 0.3 × a

a= 0.5 × 0.15/0.3

a= 0.25 m

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<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

In a given concern, mass m₁ is M, mass m₂ is 3M. Initial speed for the mass m₁ and  m₂ will be u₁=5 and u₂=0 m/s respectively,

According to the law of conservation of momentum

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The final velocity is found as;

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The velocity of block A is found as;

\rm V_f=\frac{(m_1-m_2)u_1}{m_1+m_2} +\frac{2m_2u_2}{m_1+m_2} \\\\  V_f=\frac{(M-3M)5+2\times3M\times0}{m_1+m_2} \\\\ V_f=2.5 m/s

Hence, the final velocity of the block A will be 2.5 m/sec.

To learn more about the law of conservation of momentum, refer;

brainly.com/question/1113396

#SPJ4

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Explanation:

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