When was the most gravitational potential energy stored between the model and Earth? Assume that the model's mass did not change
1 answer:
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Answer:
Total charge provided by the battery could be 900000 C.
Maximum current provided by the battery for 37 minutes could be 405.405 A
Explanation:
Rating= 250 A-h
a. Total charge:
Suppose t=1h
We konw that , replacing:
Total charge provided by the battery could be 900000 C.
b. Maximum current for 37 minutes
Maximum current provided by the battery for 37 minutes could be 405.405 A
Answer:
Work done W =1406.25 J
Explanation:
Work done on a body can be calculated using newton's 2nd laws:
F=ma
Hence acceleration of the block is given by:
Displacement of the object is given by:
Substitute the values
Now work done is given by:
W=F.S
W = 25×56.25
W =1406.25 J
Answer:
A) 10 m/s
Explanation:
We know that according to conservation of momentum,
m1v1 + m2v2 = m1u1 + m2u2 ..............(equation 1)
where m1 and m2 are masses of two bodies, v1 and v2 are initial velocity before collision and u1 and u2 are final velocities after collision respectively.
From the given data
If truck and car are two bodies
truck : m1 = 2000 Kg v1 = 5 m/s u1 = 0
car : m2 = 1000 kg v2 = 0 u2 = ?
final velocity of truck and initial velocity of car are static because the objects were at rest in the respective time.
substituting the values in equation 1, we get
(2000 x 5) + 0 = 0 + (1000 x u2)
u2 = x 5
= 10 m/s
Hence after collision, car moves at a velocity of 10 m/s