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max2010maxim [7]
3 years ago
15

When was the most gravitational potential energy stored between the model and Earth? Assume that the model's mass did not change

.​
Physics
1 answer:
Lyrx [107]3 years ago
8 0

Answer:

As the ball falls from C to E, potential energy is converted to kinetic energy. The velocity of the ball increases as it falls, which means that the ball attains its greatest velocity, and thus its greatest kinetic energy

Explanation:

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A fence 8 ft high​ (w) runs parallel to a tall building and is 24 ft​ (d) from it. Find the length​ (L) of the shortest ladder t
AveGali [126]

Answer:

25.3 ft

Explanation:

The illustration of the problem is shown the attached image.

The length of the ladder can be calculated using the Pythagoras theorem:

Hypotenuse^2 = opposite^2 + adjacent^2

The hypotenuse is the length of the ladder.

Hypotenuse = \sqrt{opposite^2 + adjacent^2}

L^2 = BC^2 + (24 + AE)^2........1

Triangle ABC is similar to triangle AEF, hence:

\frac{BC}{8} = \frac{AE + 24}{AE}

BC = \frac{8(AE + 24)}{AE}.................2

Substitute 2 into 1

L^2 = (\frac{8(AE + 24)}{AE})^2 + (24 + AE)^2

Let AE = x

L^2 = (\frac{8x + 192}{x})^2 + (24 + x)^2

    = (8 + \frac{192}{x})^2 + (24 + x)^2

Minimize L with respect to x.

2\frac{dL}{dx} = 2(8 + \frac{192}{x})(-\frac{192}{x^2}) + 2(24 + x)

       =

5 0
3 years ago
The friction of the water on a boat produces an acceleration of -10 m/s2. If the
Neko [114]

Answer:2.5s

Explanation:

Idk I guessed and got it right

7 0
3 years ago
Two Earth satellites, A and B, each of mass m, are to be launched into circular orbits about Earth’s center. Satellite A is to o
Vera_Pavlovna [14]

Answer:

Explanation:

Orbital radius of satellite A , Ra = 6370 + 6370 = 12740 km

Orbital radius of satellite B , Rb = 6370 + 19110 = 25480 km

Orbital potential energy of a satellite = - GMm / r where G is gravitational constant , M is mass of the earth and m is mass of the satellite

Orbital potential energy of a satellite A = - GMm / Ra

Orbital potential energy of a satellite B = - GMm / Rb

PE of satellite B /PE of satellite A

=  Ra / Rb

= 12740 / 25480

= 1 / 2

b ) Kinetic energy of a satellite is half the potential energy with positive value , so ratio of their kinetic energy will also be same

KE of satellite B /KE of satellite A

= 1 / 2

c ) Total energy will be as follows

Total energy = - PE + KE

- P E + PE/2

= - PE /2

Total energy of satellite B / Total energy of A

= 1 / 2

Satellite B will have greater total energy because its negative value is less.

5 0
3 years ago
Please Help! 30 points! ASAP PLZ :)
Savatey [412]
The best logical answer is A
5 0
3 years ago
Read 2 more answers
An apple is placed 20.0 cm in front of a diverging lens of focal length 10.0 cm. Find the image distance and the magnification o
jenyasd209 [6]

Answer:

Image distance of apple=-6.7 cm

Magnification of apple=0.33

Explanation:

We are given that an apple is placed 20.cm in front of a diverging lens.

Object distance=u=-20 cm

Focal length=f=-10 cm

Because focal length of diverging lens is negative.

We have to find the image distance and magnification of the apple.

Lens formula

\frac{1}{f}=\frac{1}{v}-\frac{1}{u}

Substitute the values then we get

-\frac{1}{10}=\frac{1}{v}+\frac{1}{20}

\frac{1}{v}=-\frac{1}{10}-\frac{1}{20}

\frac{1}{v}=\frac{-2-1}{20}=-\frac{3}{20}

v=-\frac{20}{3}=-6.7 cm

Image distance of apple=-6.7 cm

Magnification=m=\frac{v}{u}=\frac{-\frac{20}{3}}{-20}

Magnification of apple=\frac{1}{3}=0.33

Hence, the magnification of apple=0.33

5 0
3 years ago
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