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serious [3.7K]
3 years ago
7

When the products of a reaction have less energy than the reactants

Chemistry
1 answer:
ohaa [14]3 years ago
7 0

Answer:

the energy of the products is less than the energy of the reactants.

Explanation:

the the change is enthalpy is negative, and heat is released to the surroundings.

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What is the net force of 4N 2N!!
RSB [31]

Answer: 4 N-2 N=2 Nto the left. Change in motion: The box will move to the left. 7.)

Explanation: Please mark branliest.

8 0
3 years ago
How many moles of C2H2 are needed to react completely with 84 mol O2
Butoxors [25]

Balanced chemical equation:

2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

2 moles C2H2 ---------------- 5 moles O2
moles C2H2 ------------------ 84 moles O2

moles C2H2 = 84 * 2 / 5

molesC2H2 = 168 / 5 => 33.6 moles of C2H2
4 0
3 years ago
It takes to break an iodine-iodine single bond. Calculate the maximum wavelength of light for which an iodine-iodine single bond
Zolol [24]

The given question is incomplete. The complete question is :

It takes 151 kJ/mol to break an iodine-iodine single bond. Calculate the maximum wavelength of light for which an iodine-iodine single bond could be broken by absorbing a single photon. Be sure your answer has the correct number of significant digits.

Answer:  793 nm

Explanation:

The relation between energy and wavelength of light is given by Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

E = energy of the light  = 151 kJ= 151000 J   (1kJ=1000J)

N= moles = 1 = 6.023\times 10^{23}

h = Planck's constant  = 6.626\times 10^{-34}Js

c = speed of light  = 3\times 10^8m/s

\lambda = wavelength of light  = ?

Putting in the values:

151000J=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}Js\times 3\times 10^8m/s}{\lambda}

{\lambda}=7.93\times 10^{-7}m=793nm    1m=10^{-9}nm

Thus  the maximum wavelength of light for which an iodine-iodine single bond could be broken by absorbing a single photon is 793 nm

3 0
3 years ago
The amount of work done depends on the amount of force applied and the distance the distance the object moves.
Ulleksa [173]
I think your answer is “true”, sorry if I’m wrong and hope this helps
3 0
3 years ago
Read 2 more answers
Calculate the work, w, gained or lost by the system when a gas expands from 15 L to 45 L against a constant external pressure of
marta [7]

Answer:

Work done by the system = 4545 J

Explanation:

The expression for the calculation of work done is shown below as:

w=-P\times \Delta V

Where, P is the pressure

\Delta V is the change in volume

From the question,  

\Delta V = 45 - 15 L = 30 L

P = 1.5 atm

w=-1.5\times 30\ atmL

Also, 1 atmL = 101 J

So,  

w=-1.0\times0.75\times 101\ J=-4545\ J (negative sign implies work is done by the system)

<u>Work done by the system = 4545 J</u>

6 0
3 years ago
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