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Oliga [24]
2 years ago
7

the picture below shows two parallel wires carrying current in the same direction. what is the net force on wire 2 due to wire 1

?
Physics
1 answer:
erastovalidia [21]2 years ago
3 0

Answer:

I dont see a picture where is it?

Explanation:

I cannot see anything L question Luestion

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Which color of light has the greatest frequency?
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Violet is at the end of the spectrum so there for it has the highest frequency 
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How many nodes are in the standing wave along the wire in the given figure?
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At a particular instant the magnitude of the gravitational force exerted by a planet on one of its moons is 7 × 1021 N. Collapse
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Answer:

Fg = 4.2*10²² N

Explanation:

The gravitational force between any two masses, provided that can be approximated by point masses (comparing their diameters with the distance between them), obeys the Newton's Universal Law of Gravitation, which states that the force (always attractive) is proportional to the product of  the masses and inversely proportional to the square of the distance between them (this as a consequence of our Universe being three-dimensional), as follows:

Fg =\frac{G*m1*m2}{r^{2}}

So, if one of the masses increases 6 times, the force between them will be directly 6 times larger, so the new magnitude of the force will be as follows:

Fg₂ = Fg₁*6 = 7*10²¹ N* 6 = 4.2*10²² N

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3 years ago
If the weight of an object is greater than the weight of the water that it displaces, which is true? 1.the object will float bec
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2) Option B...............................
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4 years ago
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A crystalline grain of nickel in a metal plate is situated so that a tensile load is oriented along the [111] crystal direction
hoa [83]

Given:

Applied stress, \sigma = 0.45 MPa

Critical Resolved Stress,  T_{cRss}= 0.242 MPa

Solution:

a). According to the question, orientation of tensile load is along [1 1 1],

\sigma = 0.45 MPa

Now, for resolved shear stress,  \t_{Rss} along [1 0 1] within (1 1 T)

let  '\theta' be the angle between [1 1 1] and [1 0 1], then by coordinate formula:

cos\theta = \frac{1\times 1 + 1\times 0 + 1\times 1}{\sqrt{1^{2}+1^{2}+1^{2}\sqrt{1^{2}+0^{2}+1^{2}}}}

cos\theta = \sqrt{\frac{2}{3}}

let  '\phi' be the angle between [1 1 1] and [1  1 1], then by coordinate formula:

cos\phi  = \frac{1\times 1 + 1\times 1 + 1\times 1}{\sqrt{1^{2}+1^{2}+1^{2}\sqrt{1^{2}+1^{2}+1^{2}}}}

cos\phi = 1

Now, for the resolved components along [1 0 1]

\t_{Rss}  = \sigma  cos\theta cos\phi

\t_{Rss} = 0.45\times 10^{6}\times \sqrt{\frac{2}{3}}\times 1 = 0.3673 MPa

b).  For required tensile stress to produce  T_{cRss}= 0.242 MPa:

\sigma _{1} = \frac{T_{cRss}}{cos\theta  cos\phi }

\sigma _{1} = \frac{0.242\times 10^{6}}{\sqrt{\frac{2}{3}}\times 1}

\sigma _{1} = 0.2964 MPa

5 0
3 years ago
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