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PIT_PIT [208]
3 years ago
11

Why is temperature effective at speeding up a chemical reaction

Chemistry
1 answer:
VladimirAG [237]3 years ago
4 0

Answer:

so basically the particles move faster

Explanation:

which is made from the cause of a chemical reaction do u get it now?

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An ion that consists of 7 protons, 9 neutrons, and 10 electrons has a net charge of
nasty-shy [4]

Answer:

-3

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Protons have a positive (+) charge
  • Neutrons have a neutral (0) charge
  • Electrons have a negative (-) charge

Explanation:

<u>Step 1: Define</u>

7 protons, 9 neutrons, 10 electrons.

+7, +0, -10

<u>Step 2: FInd charge</u>

7 + 0 - 10 = -3

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3 years ago
I REALLY NEED HELP can someone help me please I’ll mark you brainliest! :)
Yanka [14]

Answer:

A

Explanation:

5 0
3 years ago
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BigorU [14]
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y=Mx+b
56x+100
6 0
2 years ago
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The value of Kc for the reaction between water vapor and dichlorine monoxide, H2O(g) 1 Cl2O(g) 4 2 HOCl(g) is 0.0900 at 25°C. De
max2010maxim [7]

Answer:

[HOCl] = 0.001 127 mol·L⁻¹; [H₂O] = [Cl₂O] = 0.003 76 mol·L⁻¹

Explanation:

The balanced equation is

H₂O + Cl₂O ⇌ 2HOCl

Data:

     Kc = 0.0900

[H₂O] = 0.004 32 mol·L⁻¹

[Cl₂O] = 0.004 32 mol

1. Set up an ICE table.

\begin{array}{ccccccc}\rm \text{H$_{2}$O}& + & \text{Cl$_{2}$O} & \, \rightleftharpoons \, & \text{2HOCl} & & \\0.00432 & & 0.00432 & & 0 & & \\-x &&-x&&+2x&&\\0.00432-x &&0.00432 - x& & 2x&&\\\end{array}

2. Calculate the equilibrium concentrations

K_{\text{c}} = \dfrac{\text{[HOCl]$^{2}$}}{\text{[H$_{2}$O][Cl$_2$O]}} = \dfrac{(2x)^{2}}{(0.00432 - x)^{2}} = 0.0900\\\\\begin{array}{rcl}\dfrac{4x^{2}}{(0.00432 - x)^{2}} &=& 0.0900\\ \dfrac{2x }{0.00432 - x} & = & 0.300\\2x & = & 0.300(0.00432 - x)\\2x & = & 0.001296 - 0.300x\\2.300x & = & 0.001296\\x & = & \mathbf{5.63\times 10^{-4}}\\\end{array}

[HOCl] = 2x mol·L⁻¹ = 2 × 5.63 × 10⁻⁴ mol·L⁻¹ =0.001 127 mol·L⁻¹

[H₂O] = [Cl₂O] = (0.004 32 - 0.000 563) mol·L⁻¹ = 0.003 76 mol·L⁻¹

Check:

\begin{array}{rcl}\dfrac{0.001127^{2}}{0.00376^{2}} & = & 0.0900\\\\\dfrac{1.270 \times 10^{-6}}{1.411 \times 10^{-5}} & = & 0.0900\\0.0900 & = & 0.0900\\\end{array}

OK.

7 0
3 years ago
Can someone please check my answer??!!!
Ksenya-84 [330]

Answer:

I think its correct

5 0
3 years ago
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