PH+pOH=14
4.5+pOH=14
pOH=14-4.5
pOH = 9.5
We know that
[H⁺][OH⁻]=10⁻¹⁴,so
-log([H⁺][OH⁻])=-log10⁻¹⁴
-log [H⁺]+ (- log[OH⁻])= - log10⁻¹⁴,
- log[H⁺] = pH
- log[OH⁻] = pOH
- log10⁻¹⁴=-(-14)log10=14*1=14
pH + pOH =14
Answer:
The type of bond formed in FeS would be <u>Polar Covalent Bond</u>.
Explanation:
Types of Bonds can be predicted by calculating the difference in electronegativity.
If, Electronegativity difference is,
Less than 0.4 then it is Non Polar Covalent Bond
Between 0.4 and 1.7 then it is Polar Covalent Bond
Greater than 1.7 then it is Ionic Bond
For Fe and S,
E.N of Sulfur = 2.58
E.N of Iron = 1.83
________
E.N Difference 0.75 (Polar Covalent Bond)
Answer:

Explanation:
Hello!
In this case, since the sulfuric acid and sodium hydroxide react in a 1:2 mole ratio, given the reaction, we realize they have the following mole ratio at the equivalence point:

Which in terms of concentrations and volumes is:

Thus, we can plug in the volume and concentration of acid to find the moles of base:

Best regards!
Answer:
Absolute error 
% Error
5
Explanation:
The absolute error is the the difference in the measured value and the actual value of a quantity.
Here the actual value is
grams
The measured value is
grams
Absolute error

Percent error

Where AE stands for absolute error and AV stands for absolute value.

%
B, C, D are compounds, while A and E are just element stand-alones.