Answer:
53.13 °
Explanation:
In order to do this, we just need to apply the following:
tanα = Dy/Dx
Where:
Vy: speed of the ball in the y axis.
Vx: speed of the ball in the x axis.
At this point we do not need the speed of the first ball after the collision because in that moment is already heading in the direction that we are looking for. Therefore, we just need to use the innitial data to calculate the direction which the first ball will go.
According to this, then:
tanα = (40/30)
tanα = 1.3333
α = tan⁻¹(1.3333)
<h2>
α = 53.13°</h2>
This means that the final direction of the first ball is 53.13° and in the x axis because the starting momentum of this ball in the x axis has not dissapeared.
Hope this helps
Displacement will be 15 too because
It falls from 0 till 15 meters
da answer is liquiddddddddd
Answer:
α =18.75 rad/s²
Explanation:
Given that
Acceleration a = 0.15 g
We know that g =10 m/s²
a= 0.15 x 10 = 1.5 m/s²
d= 16 cm
Radius r= 8 cm
Lets take angular acceleration =α rad/s²
As we know that
a= α r
Now by putting the values
1.5 = α x 0.08
α =18.75 rad/s²
Answer:
I believe the answer is B.)
