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SIZIF [17.4K]
3 years ago
7

Using the image provided, which moon phase is next?

Physics
2 answers:
ella [17]3 years ago
5 0

Answer:

Waning Crescent

Sergio [31]3 years ago
3 0

Answer: waxing crescent

Explanation:

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6. A 145-g baseball moving 30.5 m/s strikes a stationary 5.75-kg brick resting on small rollers so it moves without significant
Sindrei [870]

Answer:

Explanation:

a )

momentum of baseball before collision

mass x velocity

= .145 x 30.5

= 4.4225 kg m /s

momentum of brick after collision

= 5.75 x 1.1

= 6.325 kg m/s

Applying conservation of momentum

4.4225 + 0 = .145 x v + 6.325 , v is velocity of baseball after collision.

v = - 13.12 m / s

b )

kinetic energy of baseball  before collision = 1/2 mv²

= .5 x .145 x 30.5²

= 67.44 J

Total kinetic energy before collision = 67.44 J

c )

kinetic energy of baseball after collision = 1/2 x .145 x 13.12²

= 12.48 J .

 kinetic energy of brick after collision

= .5 x 5.75 x 1.1²

= 3.48 J

Total kinetic energy after collision

= 15.96 J

3 0
4 years ago
7,293 ÷ 8 what is this
eduard

Answer: 911.625

Explanation:

8 0
2 years ago
Read 2 more answers
a body weights 28N at a height of 3200km from the earth surface.What will be the gravitational force on that body if its lies on
alekssr [168]

Answer:

The object would weight 63 N on the Earth surface

Explanation:

We can use the general expression for the gravitational force between two objects to solve this problem, considering that in both cases, the mass of the Earth is the same. Notice as well that we know the gravitational force (weight) of the object at 3200 km from the Earth surface, which is (3200 + 6400 = 9600 km) from the center of the Earth:

F_G=G\,\frac{M_E\,m}{d^2} \\28\,\,N=G\,\frac{M_E\,m}{9600000^2}

Now, if the body is on the surface of the Earth, its weight (w) would be:

F_G=G\,\frac{M_E\,m}{d^2} \\w=G\,\frac{M_E\,m}{6400000^2}

Now we can divide term by term the two equations above, to cancel out common factors and end up with a simple proportion:

\frac{w}{28} =\frac{9600000^2}{6400000^2} \\\frac{w}{28} =\frac{9}{4} \\\\ \\w=\frac{9\,*\,28}{4}\,\,\,N\\w=63\,\,N \\

4 0
3 years ago
Solve for v<br> when<br> d = 10 and<br> t=5
VashaNatasha [74]

Answer:

asfsdfasasfsda

Explanation:

7 0
3 years ago
Read 2 more answers
Indicate whether the following statements are always true or can be false. An object's velocity will change if a net force acts
Sergio [31]

Answer:

1-An object's velocity will change if a net force acts on the object. (True)

2-In order not to slow down, a car moving at a constant velocity needs a small net force applied. (False)

3- The net force which acts on an object which remains at rest is zero. (True)

4- If an object's speed does not change, no net force is acting on the object.(True)

5- If two objects are under the influence of equal forces, they have the same acceleration. (False)

6- During the collision of a car with a large truck, the truck exerts a greater force on the car than the car exerts on the truck.(False) (Newton Third Law)

3 0
3 years ago
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