Answer:
v = 3.08 km/s
Explanation:
Given that,
The angular velocity of the satellite = 
A satellite is in orbit 36000km above the surface of the earth.
The radius of the earth is 6400 km
Let v is the velocity of the satellite. It can be calculated as :

So, the velocity of the satellite is 3.08 km/s.
Answer:
= 2.33
Explanation:
.According to snell's law:
n1sin i = n2sin r ,
where n1 is refractive index of the medium in which incident ray is travelling, n2 is the refractive index of the medium in which refracted ray is travelling,
i is angle of incidence,
r is angle of refraction.
Given that,
n1 = 1,
i = 51 degrees,
r = 19.5 degrees. ,
n2= ?
So,
1*sin 51 = n2 sin 19.5
=> n2 = sin51 / sin19.5
= 2.33
Consider that the bar magnet has a magnetic field that is acting around it, which will imply that there is a change in the magnetic flux through the loop whenever it moves towards the conducting loop. This could be described as an induction of the electromotive Force in the circuit from Faraday's law.
In turn by Lenz's law, said electromotive force opposes the change in the magnetic flux of the circuit. Therefore, there is a force that opposes the movement of the bar magnet through the conductor loop. Therefore, the bar magnet does not suffer free fall motion.
The bar magnet does not move as a freely falling object.
Answer:
Equilibrium quantity = 5
Equilibrium price = 40
Explanation:
given:
p = -x²-3x+80
p = 7x+5
For the equilibrium quantity the price from both the functions will be equal
thus, we have
-x² - 3x + 80 = 7x+5
⇒ x² +3x + 7x + 5 - 80 = 0
⇒x² + 10x - 75 = 0
now solving for x
x²- 5x + 15x -75 = 0
x(x-5) + 15(x-5) = 0
therefore, the two roots of the equation are
x = 5 and x = -15
since the quantity cannot be in negative
therefore, the equilibrium quantity will be = 5
now the equilibrium price can be found out by substituting the equilibrium quantity in any of the equation
thus,
p = -(5)² -3(5) + 80 = 40
or
p = 7(5) + 5 = 40
The momentum of an object is given by:

where
p is the momentum
m is the mass
v is the velocity of the object
The ball in our problem has a mass of m=1.0 kg and a momentum of

, therefore we can use the previous formula to find its velocity: