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2 years ago

How do you find the net force acting on an object?

1 answer:

6 0

It's D. By "net" they mean the overall force the object experiences, so sum all the force vectors, those in a negative direction (eg friction) should be subtracted.

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A cart is pulled by a force of 250 N at an angle of 35° above the horizontal. The cart accelerates at 1.4 m/s2. The free-body di

Vikki [24]

Answer:

Mass of the cart = 146 kg

Explanation:

A cart is pulled by a force of 250 N at an angle of 35° above the horizontal.

The cart accelerates at 1.4 m/s² horizontally.

Horizontal force = Fcosθ = 250 cos35° = 204.79N

We have F = ma

Substituting

204.79 = m x 1.4

m = 146.28 kg = 146 kg

Mass of the cart = 146 kg

3 0

2 years ago

The circuits, P and Q, show two different ammeter-voltmeter methods of measuring resistance. Suppose the ammeter has a resistanc

qaws [65]

Answer:

Uncorrected values for

For circuit P

R = 2.4 ohm

For circuit Q

R = 2.4 ohm

Corrected values

for circuit P

R = 12 OHM

For circuit Q

R = 2.3 ohm

Explanation:

Given data:

Ammeter resistance 0.10 ohms

Resister resistance 3.0 ohms

Voltmeter read 6 volts

ammeter reads 2.5 amp

UNCORRECTED VALUES FOR

1) circuit P

we know that IR =V

$R = \frac{6}{2.5} - 2.4 ohm$

2) circuit Q

R = 2.4 ohm as no potential drop across ammeter

CORRECTED VALUES FOR

1) circuit p

IR = V

$\frac{3R}{R+3} \times 2.5 = 6$

R= 12 ohm

2) circuit Q

$I\times (R+0.1) =V$

$R+0.1 =\frac{6}{2.5}$

R = 2.3 ohm

5 0

3 years ago

HELP - What are some good topics to add to a Pipeline presentation? So yes, a presentation about pipelines, like for example in

In-s [12.5K]

Talk about the jobs that pipeline construction provides to citizens and wether or not it’s effects are ultimately eco-friendly

6 0

2 years ago

5. Stopping a fast-moving object is harder than stopping a slow-moving<br> one.<br> True<br> False

Strike441 [17]

True because well it’s moving fast lol sometimes ur eyes have a hard time following its speed

6 0

2 years ago

Read 2 more answers

A 70-kg ice skater is standing still on the ice, when a friend tosses him a 10-kg ball that is traveling at +8 m/s. If he catche

Misha Larkins [42]

Answer:+1.25 m/s

Explanation:

Given

mass of ice skater M=70 kg

mass of ball m=10 kg

the initial velocity of the ball $u_1=+8\ m/s$

Conserving linear momentum

$M\times0+m\timesu_1=(M+m)v\quad \quad [v=\text{combined velocity of skater and ball}]$

$v=\dfrac{10\times10}{80}=+1.25\ m/s$

Therefore the velocity of the person holding the ball is 1.25 m/s

This collision represents the perfectly inelastic collision where particles stick together after the collision.

7 0

2 years ago