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leva [86]
2 years ago
9

As ___ increases,___ increases

Chemistry
1 answer:
Goshia [24]2 years ago
8 0

Answer:

if the force applied increases

if the area of contact increases

Explanation:

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Which statement would support a merit of the Bronsted-Lowry base theory has over the Arrhenius base theory?
butalik [34]

Answer:

Explanation:

Bronsted Base is an H+ acceptor

No good answer Bronstead base does not accept hydroxide or electrons

5 0
3 years ago
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Why is steam distillation prefered over fractional distillation for the extraction of essencial oils?​
frez [133]

Answer:

Because , the advantage of steam distillation over simple distillation is that the lower boiling point reduces decomposition of temperature-sensitive compounds. Steam distillation is useful for the purification of organic compounds, although vacuum distillation is more common

Explanation:

7 0
3 years ago
The table compares the number of electrons in two unknown neutral atoms.
Andrej [43]

Answer:

Both are highly reactive.

Explanation:

A has 1 valence electron D has 3

A is sodium D is aluminum

5 0
3 years ago
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How many moles of water are produced if 5.43 mol PbO2 are consumed?<br><br> ANSWER: 10.9
Arada [10]

Answer: 10.9 mol.

Explanation:

  • To understand how to solve this problem, we must mention the reaction equation where water produced from PbO₂.

Pb + PbO₂ + 2H₂SO₄ → 2PbSO₄ + 2H₂O

  • Now, it is a stichiometric oriented problem, that 1 mole of PbO₂ produces 2 moles of H₂O.

Using cross multiplication:

1.0 mole of PbO₂ → 2.0 moles of H₂O

5.43 moles of PbO₂ → ??? moles of water

The moles of water produced = (5.43 x 2.0) = 10.86 moles ≅ 10.9 moles.

4 0
3 years ago
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if 30.0L of oxygen are cooled from 200 degrees celsius to 1 degree celsius at constant pressure, what is the new volume of oxyge
Sergio039 [100]

Answer: 18.65L

Explanation:

Given that,

Original volume of oxygen (V1) = 30.0L

Original temperature of oxygen (T1) = 200°C

[Convert temperature in Celsius to Kelvin by adding 273.

So, (200°C + 273 = 473K)]

New volume of oxygen V2 = ?

New temperature of oxygen T2 = 1°C

(1°C + 273 = 274K)

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

30.0L/473K = V2/294K

To get the value of V2, cross multiply

30.0L x 294K = 473K x V2

8820L•K = 473K•V2

Divide both sides by 473K

8820L•K / 473K = 473K•V2/473K

18.65L = V2

Thus, the new volume of oxygen is 18.65 liters.

5 0
3 years ago
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