｡☆✼★ ━━━━━━━━━━━━━━ ☾
I believe the answer would be A. equal temperature
Have A Nice Day ❤
Stay Brainly! ヅ
- Ally ✧
｡☆✼★ ━━━━━━━━━━━━━━ ☾
Answer:
3.82 x 10²¹ molecules As₂O₃
Explanation:
To find the amount of molecules arsenic (III) oxide (As₂O₃), you need to (1) convert kg to lbs, then (2) convert g As₂O₃ to moles As₂O₃ (via molar mass), and then (3) convert moles to molecules (via Avogadro's number).
1 kilogram = 2.2 lb
Molar Mass (As₂O₃): 2(74.992 g/mol) + 3(15.998 g/mol)
Molar Mass (As₂O₃): 197.978 g/mol
Avogadro's Number:
6.022 x 10²³ molecules = 1 mole
0.0146 g As₂O₃ 1 kg 189 lb
------------------------ x --------------- x ------------------ x ................
1 kg 2.2 lb
1 mole 6.022 x 10²³ molecules
x ------------------ x --------------------------------------- = 3.82 x 10²¹ molecules As₂O₃
197.978 g 1 mole
Answer:
Both molarity and formality express concentration as moles of solute per liter of solution. Formality is a substance's total concentration in solution without regard to its specific chemical form. ... The formality of a solution is defined as the number of formula mass of any solute dissolved in 1 litre of solution.
Answer:
7.335 moles of Cl₂ are required to react with 4.89 miles of Al.
Explanation:
Given data:
Moles of Al = 4.89 mol
Number of moles of Cl₂ required = ?
Solution:
Chemical equation:
2Al + 3Cl₂ → 2AlCl₃
Now we will compare the moles of Al and chlorine from balance chemical equation.
Al : Cl₂
2 : 3
4.89 : 3/2×4.89 =7.335 mol
Thus, 7.335 moles of Cl₂ are required to react with 4.89 miles of Al.
