Question

A peach pie in a 9.00 in diameter plate is placed upon a rotating tray. Then, the tray is rotated such that the rim of the pie plate moves through a distance of 208 in. Express the angular distance that the pie plate has moved through in revolutions, radians, and degrees.

Answer 1

Answer:

a)  $X_1=7.36rev$

b)  $X_2=46.22radians$

c) $X_3=2649.6^o$

Explanation:

From the question we are told that:

Diameter $d=9.00$

Distance $x=208$

Generally the equation for circumference of a circle is mathematically given by

$C=2 \pi r\\\\C=2*\pi*4.5$

$C=28.3$

Therefore

Angular distance that the pie plate has moved through in revolutions is

$X_1=\frac{x}{C}$

$X_1=\frac{208}{28.3}$

$X_1=7.36rev$

Generally Angular distance that the pie plate has moved through in radians is

$X_2= 7.36rev* 2 \pi$

$X_2=46.22radians$

Generally Angular distance that the pie plate has moved through in degrees is

$X_3=7.36rev* 360$

$X_3=2649.6^o$