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Allisa [31]
2 years ago
8

All celestial objects we tracted to each other by gravity.Asteroids A and B are 5 meters (m) part. Asteroids C and D are also 5

m apart. Asteroids A and B both have a mass of 5 kilograms(kg) and asteroids C and D both have a mass of 7 kg.Between which set of asteroids is the gravitational attraction?
A between asteroids c and d because gravitational attraction is greatest with increased mass

B between asteroids a and b because gravitational attraction is greatest with decreased mass

C between asteroids a and b because gravitational attraction is greatest with increased distance

D between asteroids c and d because gravitational attraction is greatest with increased distance
Physics
1 answer:
Nadusha1986 [10]2 years ago
6 0
A. Between asteroids C and D because gravitational attraction is greatest with increased mass.
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ipn [44]

Answer:

well the answers are 180 and 240 obviously

Explanation:

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2 years ago
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natita [175]
The answer is b) venus because the period rotation is also referred to as a day so if venus’ period of rotation is 243 [earth] days and its year is 225 [earth] days, then the period of rotation is longer.
5 0
2 years ago
An electron with speed 2.45 x 10^7 m/s is traveling parallel to a uniform electric field of magnitude 1.18 x 10^4N/C . How much
cupoosta [38]

Answer:

time will elapse before it return to  its staring point is 23.6 ns

Explanation:

given data

speed u = 2.45 × 10^{7} m/s

uniform electric field E = 1.18 × 10^{4} N/C

to find out

How much time will elapse before it returns to its starting point

solution

we find acceleration first by electrostatic force that is

F = Eq

here

F = ma by newton law

so

ma = Eq

here m is mass , a is acceleration and E is uniform electric field and q is charge of electron

so

put here all value

9.11 × 10^{-31} kg ×a = 1.18 × 10^{4} × 1.602 × 10^{-19}

a = 20.75 × 10^{14} m/s²

so acceleration is 20.75 × 10^{14} m/s²

and

time required by electron before come rest is

use equation of motion

v = u + at

here v is zero and u is speed given and t is time so put all value

2.45 × 10^{7} = 0 + 20.75 × 10^{14} (t)

t = 11.80 × 10^{-9} s

so time will elapse before it return to  its staring point is

time = 2t

time = 2 ×11.80 × 10^{-9}

time is 23.6 × 10^{-9} s

time will elapse before it return to  its staring point is 23.6 ns

7 0
2 years ago
How many joules of work are done on a box when a force of 25 N pushes it 3 m?
Anika [276]

Answer:

75joules

Explanation:

Workdone = force x distance

workdone = 25 x 3

workdone = 75joules

7 0
2 years ago
a hotgas is injected into at engine at 573 k and exhausts at 343 k. what is the highest efficiency of thisengine?
Dovator [93]

Answer:

230k

Explanation:

energy capacity maximum is 573 total available. 343k of that energy is present at release and subsequent loss leaving max used energy of 230k.

4 0
2 years ago
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