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Crazy boy [7]
3 years ago
13

Compare the density of a 1,000,000 kg iceberg to that of a 10 g ice cube taken from the

Physics
1 answer:
drek231 [11]3 years ago
3 0

Answer:

The density of the 1,000,000 kg iceberg = The density of the 10 g iceberg

Explanation:

The given quantities of iceberg that will be the basis of the comparison of the densities of the iceberg;

The mass of the iceberg = 1,000,000 kg

The mass of the ice cube taken from the iceberg = 10 g

The density of a substance, is the measure of the mass of the substance per volume of the substance, it is a constant for the substance

Density = \dfrac{Mass}{Volume}

For the iceberg, the density of the iceberg is the property that indicates the volume occupied by a given mass of the iceberg

Because of density, we can estimate that the volume occupied by a 1,000 kg iceberg is 10 times the volume occupied by a 100 kg iceberg

We can write

The density of the 100 kg iceberg = 100 kg/(x m³)

The density of the 1,000 kg iceberg = 1,000 kg/(10 × x m³) = 100 kg/(x m³)

Therefore, the density of the 100 kg iceberg = The density of the 1,000 kg iceberg

Similarly,

The density of the 1,000,000 kg iceberg = The density of the 10 g iceberg because the 10 g iceberg was obtained from the 1,000,000 kg iceberg, and therefore, they have the same density.

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The elements from this section of the periodic table all belong to the same
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The answer is:

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3 years ago
A projectile is launched
Flauer [41]

The vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.

The given parameters;

  • initial horizontal velocity, vₓ = 16 m/s
  • initial vertical velocity, v_y =0
  • time interval 1 seconds

The components of the velocity can be horizontal or vertical velocity.

The vertical component of the velocity is affected by acceleration due to gravity while the horizontal component of the velocity is not affected by gravity.

The vertical component of the velocity is calculated as;

v_y = v_0_y -gt\\\\v_y = 0 - (1\times 9.8)\\\\v_y = -9.8 \ m/s

The horizontal component of the velocity is constant since it is not affected by gravity.

The horizontal component of the velocity = 16 m/s

Thus, the vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.

Learn more here:brainly.com/question/20349275

4 0
3 years ago
A 1500 kg car traveling east at 40 km/hr turns a corner and speeds up to a velocity of 50 km/hr due north. What is the change in
pantera1 [17]

Answer:

96046  Ns.

Explanation:

We shall represent velocity in vector form considering east direction as + ve x axis and north as + y direction.

40 km/h in the east

V₁ = 40 i

V₂ = 50j

momentum p₁ = mV₁

= 1500 X 40 i

= 60000 i

Momentum p₂ = mV₂

= 1500 X 50j

= 75000 j

Change in momentum

p₂ - p₁

75000j - 60000i

Magnitude of change

= \sqrt{(750000)^2 +(60000)^2

= 96046  Ns.

5 0
3 years ago
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