Answer:
![5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}](https://tex.z-dn.net/?f=5.31%2A10%5E%7B-10%7D%20%3D%20%5Cfrac%7B%5B%5DH_%7B2%7D%5D%5E%7B2%7D%5BO_%7B2%7D%5D%7D%7B%5BH_%7B2%7DO%5D%5E%7B2%7D%7D)
Explanation:
For a chemical reaction, equilibrium is a state at which the rate of the forward reaction equals that of the reverse reaction. The equilibrium constant Keq is a parameter characteristic of this state which is expressed as a ratio of the concentration of the products to that of the reactants.
For a hypothetical reaction:
xA + yB ⇄ zC
The equilibrium constant is :
![Keq = \frac{[A]^{x}[B]^{y}}{[C]^{z} }](https://tex.z-dn.net/?f=Keq%20%3D%20%5Cfrac%7B%5BA%5D%5E%7Bx%7D%5BB%5D%5E%7By%7D%7D%7B%5BC%5D%5E%7Bz%7D%20%7D)
The given reaction involves the decomposition of H2O into H2 and O2
The equilibrium constant is expressed as :
![Keq = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}](https://tex.z-dn.net/?f=Keq%20%3D%20%5Cfrac%7B%5B%5DH_%7B2%7D%5D%5E%7B2%7D%5BO_%7B2%7D%5D%7D%7B%5BH_%7B2%7DO%5D%5E%7B2%7D%7D)
Since Keq = 5.31*10^-10
Answer:
0.39760273
Explanation:
I typed into calculator hope it's right.
There are several differences between a physical and chemical change in matter or substances. A physical change in a substance doesn't change what the substance is. In a chemical change where there is a chemical reaction, a new substance is formed and energy is either given off or absorbed.
Answer:
3.96 MINUTES
Explanation:
Karl likes to use cruise control when he drives on
the highway. After setting cruise control at 33.53
m/s (75 mph). At this speed, how long would it
take Karl to travel 8 kilometers?
VELOCITY = DISTANCE/TIME
OR
V=D/T
SO
VT=D
SO
T=D/V
THE DISTANCE IS 8 KM
THE VELOCITY IS 75 MPH
THERE ARE 1.61 KM PER MILE
SO
75M[H =
75 X 1.61 KM/H =
121 KM/HR
T=D/V
T=8/121 =0.066 HOUR =
0.066 X 60 MINUTES =
3.96 MINUTES
CHECK
75 MPH =
(75 X 1.61) KM/60 MINUTES =
120,75 KM/60 MINUTES=
2.01 KM/MINUTE
to travel 8 K,M WILL TAKE
8/2.01 = 3.98 minutes
Answer:
D.) 4
Explanation:
Al + 3 O₂ --> 2 Al₂O₃
In the equation, there are:
<em>Reactants:</em> 1 Al and 6 O
<em>Products:</em> 4 Al and 6 O
To determine how many atoms there are of each, you multiply the coefficients by the subscripts attached to the atoms. While the question doesn't ask, as you can see, the oxygen atoms are balanced because there is an equal amount on both sides. To balance the aluminum atoms, you can get 4 aluminum atoms on the reactants side by using a coefficient of 4.
The new equation would look this this:
4 Al + 3 O₂ --> 2 Al₂O₃
There are now:
<em>Reactants:</em> 4 Al and 6 O
<em>Products:</em> 4 Al and 6 O
