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madam [21]
3 years ago
5

Which one is harder, magnesium or calcium, and why?

Chemistry
1 answer:
koban [17]3 years ago
8 0
Magnesium, because it is responsible for more than 300 biochemical reactions and because it’s a solid.
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How many grams of ZNO shoulbe added to 30gms of 10%ZNO to get 15%oint​
patriot [66]

Mass of ZnO added=1.765 g

<h3>Further explanation:</h3>

Given

30gms of 10%ZnO(Zinc oxide)

15% ZnO

Required

mass of ZnO added

Solution

Amount of ZnO in 30 gms of 10% ZnO =3 gms

For 15% ZnO : x= ZnO added

New solution = 30+x = 15%, so the equation :

\tt \dfrac{3+x}{30+x}=15\%\\\\15\%(30+x)=3+x\\\\4.5+0.15x=3+x\\\\1.5=0.85x\\\\x=1.765~gms

3 0
3 years ago
Read 2 more answers
Which chemical equation is unbalanced?
Travka [436]

Answer:

Sr + O2 → 2SrO would be an unbalanced equation.

Explanation:

There is only one Sr on the left, and two on the right.

7 0
3 years ago
Read 2 more answers
Measurement of heat conductivity A metal panel of area A = 100 cm² and thickness Y = 0.5 cm was found to conduct heat at a rate
RSB [31]

Answer:

The average thermal conductivity of the material at this temperature range is 3*10^(-9) W/mK.

Explanation:

The heat flow through this area of the metal panel can be expressed as:

q/A=-k\frac{(T_2-T_1)}{Y}

being A the surface area, k the thermal conductivity, T2 and T1 the temperatures in each side and Y the thickness of the metal panel.

We have to rearrange the equation to clear k:

k=\frac{-(q/A)*Y}{\Delta T} = \frac{-(3 W/100 cm2)*0.5cm}{5 ^\circ K}*(\frac{1m}{100cm} )^{3} \\\\k=\frac{0.015}{5*100^{3} }W/mK= 3*10^{-9}W/mK

The average thermal conductivity of the material at this temperature range is 3*10^(-9) W/mK.

7 0
3 years ago
A system is composed of 7.14 grams of Ne gas at 298 K and 1 atm. When 2025 joules of heat are added to the system at constant pr
dlinn [17]

Answer:

(a) 1 atm, 8.72 L and 298 K respectively.

(b) 1 atm, 16.72 L and 573.35 K respectively.

(c) \Delta U=1215J

Explanation:

Hello,

(a) In this case, considering that neon could be considered as an ideal gas, we can compute its volume as follows:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{7.14g*\frac{1mol}{20g}0.082\frac{atm*L}{mol*K}*298K}{1atm}\\  \\V=8.72L

Thus, initial conditions of pressure volume and temperature are 1 atm, 8.72 L and 298 K respectively.

(b) Since the process was carried out at constant pressure, the work is defined as:

W=P(V_2-V_1)

Thus, the final volume is:

V_2=\frac{W}{P} +V_1=\frac{810Pa*m^3}{1atm*\frac{101325Pa}{1atm} } *\frac{1000L}{1m^3}+8.72L\\ \\V_2=16.72L

And the final temperature is computed by considering the pressure-constant specific heat of neon (1.03 J/g*K) and the added heat:

Q=mCp(T_2-T_1)\\\\T_2=\frac{Q}{mCp}+T_1 =\frac{2025J}{7.14g*1.03J/(g*K)}+298K\\ \\T_2=573.35K

Therefore, final volume is 16.72 L, final pressure is also 1 atm and final temperature is 573.35 K for this expansion process.

(c) Finally, the change in the internal energy is computed via the first law of thermodynamics:

Q-W=\Delta U\\\\\Delta U=2025J-810J\\\\\Delta U=1215J

Best regards.

8 0
3 years ago
State one function of Emitter??​
stellarik [79]

Answer:

To emit

Explanation:

yea

7 0
3 years ago
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