To place the poles of a 1. 5 v battery to achieve the same electric field is 1.5×10−2 m
The potential difference is related to the electric field by:
∆V=Ed
where,
∆V is the potential difference
E is the electric field
d is the distance
what is potential difference?
The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.
We want to know the distance the detectors have to be placed in order to achieve an electric field of
E=1v/cm=100v/cm
when connected to a battery with potential difference
∆v=1.5v
Solving the equation,we find
learn more about potential difference from here: brainly.com/question/28166044
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Answer:
formula used K=F/∆l
∆l is the elongation of the spring
- F=10N
- ∆l=20mm===> 0.02m
- K=10N divided 0.02m= 500N/m
Please state the options and I will answer to the best of my abilities XD
Scientists review the work of other scientists to validate the results and check the evidence's reliability. The correct option among all the options that are given in the question is the fourth option or the last option or option "D". I hope that this is the answer that has come to your desired help.
Answer:
F= 0.6321 N
Explanation:
Given
Area ,A= 14 cm²
Density ,ρ = 1.204 kg/m³
Velocity ,v= 50 m/s
Drag coefficient ,C=0.3
The drag force on the golf given as
Now by putting the values
F= 0.6321 N
Therefore force due to drag on the golf is 0.6321 N