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3 years ago

How does light travel through a solid, liquid, gas, and a vacuum?

Chemistry

2 answers:

Mariana [72]3 years ago

4 0

Answer:

Answer:

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thats why i got straight A's unlike uAnswer:

i work hard for my grades i pay attention in school

Explanation:

thats why i got straight A's unlike uAnswer:

i work hard for my grades i pay attention in school

Explanation:

thats why i got straight A's unlike uAnswer:

i work hard for my grades i pay attention in school

Explanation:

thats why i got straight A's unlike uAnswer:

i work hard for my grades i pay attention in school

Explanation:

thats why i got straight A's unlike uAnswer:

i work hard for my grades i pay attention in school

Explanation:

thats why i got straight A's unlike uAnswer:

i work hard for my grades i pay attention in school

Explanation:

thats why i got straight A's unlike uv

Explanation:

REY [17]3 years ago

3 0

Light travels in a straight line as a wave. It does not require any medium or material to travel like sound waves which means it can travel in vacuum.The speed of the light from the special theory of relativity is a constant value of 38x10^8m/second

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A voltaic cell consists of a Zn>Zn2+ half-cell and a Ni>Ni2+ half-cell at 25 °C. The initial concentrations of Ni2+ and Zn

nlexa [21]

Answer :

(a) The initial cell potential is, 0.53 V

(b) The cell potential when the concentration of $Ni^{2+}$ has fallen to 0.500 M is, 0.52 V

(c) The concentrations of $Ni^{2+}$ and $Zn^{2+}$ when the cell potential falls to 0.45 V are, 0.01 M and 1.59 M

Explanation :

The values of standard reduction electrode potential of the cell are:

$E^0_{[Ni^{2+}/Ni]}=-0.23V$

$E^0_{[Zn^{2+}/Zn]}=-0.76V$

From this we conclude that, the zinc (Zn) undergoes oxidation by loss of electrons and thus act as anode. Nickel (Ni) undergoes reduction by gain of electrons and thus act as cathode.

The half reaction will be:

Reaction at anode (oxidation) : $Zn\rightarrow Zn^{2+}+2e^-$ $E^0_{[Zn^{2+}/Zn]}=-0.76V$

Reaction at cathode (reduction) : $Ni^{2+}+2e^-\rightarrow Ni$ $E^0_{[Ni^{2+}/Ni]}=-0.23V$

The balanced cell reaction will be,

$Zn(s)+Ni^{2+}(aq)\rightarrow Zn^{2+}(aq)+Ni(s)$

First we have to calculate the standard electrode potential of the cell.

$E^o=E^o_{cathode}-E^o_{anode}$

$E^o=E^o_{[Ni^{2+}/Ni]}-E^o_{[Zn^{2+}/Zn]}$

$E^o=(-0.23V)-(-0.76V)=0.53V$

(a) Now we have to calculate the cell potential.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Ni^{2+}]}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_{cell}$ = emf of the cell = ?

Now put all the given values in the above equation, we get:

$E_{cell}=0.53-\frac{0.0592}{2}\log \frac{(0.100)}{(1.50)}$

$E_{cell}=0.49V$

(b) Now we have to calculate the cell potential when the concentration of $Ni^{2+}$ has fallen to 0.500 M.

New concentration of $Ni^{2+}$ = 1.50 - x = 0.500

x = 1 M

New concentration of $Zn^{2+}$ = 0.100 + x = 0.100 + 1 = 1.1 M

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Ni^{2+}]}$

Now put all the given values in the above equation, we get:

$E_{cell}=0.53-\frac{0.0592}{2}\log \frac{(1.1)}{(0.500)}$

$E_{cell}=0.52V$

(c) Now we have to calculate the concentrations of $Ni^{2+}$ and $Zn^{2+}$ when the cell potential falls to 0.45 V.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}+x]}{[Ni^{2+}-x]}$

Now put all the given values in the above equation, we get:

$0.45=0.53-\frac{0.0592}{2}\log \frac{(0.100+x)}{(1.50-x)}$

$x=1.49M$

The concentration of $Ni^{2+}$ = 1.50 - x = 1.50 - 1.49 = 0.01 M

The concentration of $Zn^{2+}$ = 0.100 + x = 0.100 + 1.49 = 1.59 M

5 0

3 years ago

If a catalyst is used in a reaction,

Ann [662]

If a catalyst is used in a reaction, C. The reaction rate increases.

4 0

3 years ago

What is the product of SO2+H2O.

Mariulka [41]

Answer:

H2O + SO2 → H2SO3

Explanation:

H2O + SO2 → H2SO3

6 0

3 years ago

Read 2 more answers

What percent of Earths feshwater is found as a solid?

Zanzabum

Answer:

68.7% is the percent of frozen freshwater.

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3 years ago

Is it beneficial to the US economy if Russia takes over Ukraine?

seraphim [82]

Answer:

No, (But it is all that is the only way out of world war3)

Explanation:

If they take over Ukraine, Russia will now own all the oil and land that Ukraine uses to farm. It would mostly benefit Russia than the U.S

But if Ukraine gives itself up it can prevent a nuclear war between countries. Although it won't benefit the U.S, it wouldn't hurt it either. So the answer is no, it would not benefit the U.S.

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3 years ago