Answer:
0.712 moles of NO₂ are formed.
Explanation:
First, we need to write the balanced equation:
2 N₂O₅(g) ⇄ 4 NO₂(g) + O₂(g)
From the balanced equation, we can see the relationship between the moles of N₂O₅ and the moles of NO₂. Every 2 moles of N₂O₅ that react, 4 moles of NO₂ are formed. Let us apply this relationship to the information given by the problem (0.356 moles of N₂O₅):
Answer: Rate law=, order with respect to A is 1, order with respect to B is 2 and total order is 3. Rate law constant is
Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
k= rate constant
x = order with respect to A
y = order with respect to A
n = x+y = Total order
a) From trial 1: (1)
From trial 2: (2)
Dividing 2 by 1 :
therefore y=2.
b) From trial 2: (3)
From trial 3: (4)
Dividing 4 by 3:
, x=1
Thus rate law is
Thus order with respect to A is 1 , order with respect to B is 2 and total order is 1+2=3.
c) For calculating k:
Using trial 1:
.
Molarity is defined as the ratio of number of moles to the volume of solution in litres.
The mathematical expression is given as:
Here, molarity is equal to 1.43 M and volume is equal to 785 mL.
Convert mL into L
As, 1 mL = 0.001 L
Thus, volume = = 0.785 L
Rearrange the formula of molarity in terms of number of moles:
n =
= 1.12255 mole
Now, Number of moles =
Molar mass of potassium hydroxide = 56.10 g/mol
1.12255 mole =
mass in g =
= 62.97 g
Hence, mass of = 62.97 g