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fgiga [73]
2 years ago
10

2.3 The motion of an object is accelerated

Physics
1 answer:
alekssr [168]2 years ago
6 0

Answer:

The motion of an object is accelerated when its speed increases.

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What minimum volume must the slab have for a 75.0 kgkg woman to be able to stand on it without getting her feet wet
Alisiya [41]

V = 0.9375 m3 is minimum volume .

<h3>What is density ?</h3>
  • We use the word "density" to indicate how much space (or "volume") an object or substance occupies in relation to the amount of matter contained therein (its mass).
  • Density can also be defined as the quantity of mass per unit of volume. A dense object is one that is both hefty and small.

Given,

            1000 kg/m3 = density of water

             920 kg/m3 = density of ice

BF = Woman Weight + Slab Weight

Pvg = 75 + Pvg

V = 75 kg / (1000 - 920)

V = 75 / 80

V = 0.9375 m3

Therefore, V = 0.9375 m3 is minimum volume .

Learn more about density

brainly.com/question/952755

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2 years ago
(1) A Newton is 1 kgm/s2 . Is this a fundamental unit or a derived unit?
Mrac [35]
A Newton is a derived unit.
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2 years ago
When in orbit, a satellite such as the space shuttle is
My name is Ann [436]
When in orbit, a satellite such as the space shuttle s <span>in non-accelerated motion. </span>
8 0
3 years ago
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I’m which medium does sound travel fastest railroad track or across the room
blondinia [14]
The closer the particles, the more will be the propogation of sound waves. Room contains air molecules which are far away from each other. So it takes much time for one molecule of air to disturb the other one. But in case of solids, as particles are much closer(compared to fluids), disturbance generated by one molecule is quickly transmitted to the next molecule
3 0
2 years ago
A cannon ball is shot straight upward with a velocity of 72.50 m/s. How high is the cannon ball above the ground 3.30 seconds af
disa [49]

Answer:

Explanation:

Given

Cannon is fired with a velocity of u=72.50\ m/s

Using Equation of motion

y=ut+\frac{1}{2}at^2

where

y=displacement

u=initial\ velocity

a=acceleration

t=time

after time t=3.3 s

y=72.50\times 3.3-\frac{1}{2}\times 9.8\times (3.3)^2

y=239.25-53.36

y=185.89\ m

So after 3.3 s cannon ball is at a height of 185.89 m

6 0
3 years ago
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