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Talc is not soluble in water, but it is slightly soluble in dilute mineral acids. In any case, solving it will keep intact its structure. This is naturally true for the case of silicates, which are characteristics by their insolubility.
A is milk in water, actually is does not have to be in water since milk already is a mixture of fats and water. ... A colloid is just a mixture where a substance of dispersed insoluble particles is suspended throughout another substance. Chalk powder is very little soluble in water therefore this will form an suspension.
The ph of a solution is 3.7
Solution:
According to the equaiton of Henderson-Hasselback
pH= pKa+ log(salt/acid)
here it is given the value of
pKa= 4.7
So,
pH = pKa+ log(0.1/0.01)
= 4.7 + log(0.1)
= 4.7–1
= 3.7.
The following problem illustrates how the Henderson-Hasselbalch equation can be used to determine how much acid and conjugate base should be combined to create a buffer solution with a specific pH.
To learn more click the given link
brainly.com/question/13423434
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I believe it is A accumulation of lactic acid in the muscles of her limbs.
1.) A compound is a thing that is composed of two or more (separate) elements.
2.) A compound cannot be separated easily, while its properties differ from where it originates from. It also is formed from chemical reactions.
3.) A pure substance, also known as chemical substance, is a material with constant composition and consistant properties.
4.) If a substance is not a pure substance, then it is an impure substance.
Hope this helped. :)
Reaction between aluminium and oxygen can be represented as:
4Al(s) + 3O₂(g) ----->2Al₂O₃(s)
Number of moles of aluminium = Mass of aluminium/ Molar mass of aluminium
=4.2g /26.981 g / mol
=0.155 mol
The equation shows that these react with 0.155 * 3/4 moles of O2 = 0.11 moles of O2.
1 mole of O2 at STP occupies 22.4 liter
volume of O2 = 0.11 moles ×22.4 liters / mol
= 2.61 liter of O2.
