From the stoichiometry of the reaction, the mass of barium nitrate produced is 54.9 g.
<h3>Stoichiometry</h3>
The term stoichiometry refers to mass - volume relationships. Stoichiometry can be used to calculate the amount, mass or volume of reactants and products from the balanced reaction equation.
The equation of the reaction is written as follows;
BaCO3 + 2HNO3 ------> Ba(NO3)2 + CO2 + H2O
Number of moles of BaCO3 = 55 g/197.34 g/mol = 0.28 moles
Number of moles of HNO3 = 26 g/63.01 g/mol = 0.41 moles
From the reaction equation;
1 mole of BaCO3 reacts with 2 moles of HNO3
0.28 moles of BaCO3 reacts with 0.28 moles × 2 moles/1 mole = 0.56 moles
There is not enough HNO3 hence it is the limiting reactant.
Number of moles of Ba(NO3)2 produced is obtained from;
2 moles of HNO3 yields 1 mole of Ba(NO3)2
0.41 moles of HNO3 yields 0.41 moles × 1 mole/2 moles
= 0.21 moles of Ba(NO3)2
Mass of Ba(NO3)2 = 0.21 moles × 261.337 g/mol = 54.9 g
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Answer:
Explanation:
To interpret this pedigree, let’s start with information that we already know:
Brown is recessive, which means brown individuals must have the phenotype BB. In this pedigree, brown individuals are filled in.
Black is dominant, which means black individuals must have at least one B allele. Their phenotype could be either BB or BB. In this pedigree, black individuals are not filled in.
Figure 5 shows the same pedigree, but with information about the individual’s phenotype filled in.
The shaded individual, who is a brown female puppy, must have the phenotype BB. If she had any B alleles, she would be black because the black allele is dominant over the brown allele.
In order for the brown puppy to have the phenotype BB, she must have gotten two “b” alleles: one from each of her parents. We know that her parents are both black (because they are unshaped), which means they must have a least one “B” allele. This means that both parents must be heterogeneous: BB.
The three black puppies must have at least one “B” allele in order for them to be black in color. However, we can’t tell whether they are homologous dominant (BB) or heterogeneous (BB) since both of those phenotype would result in black color. One way to represent this on a pedigree is B-, meaning that the second allele could be either B or b.
Answer:
The pH of the solution is 4.28
Explanation:
The dissolution reaction as below
CH₃COOH ⇔ CH₃COO⁻ + H⁺
Assume the concentration of the ion, [H⁺] = a,
so [CH₃COO⁻] = a and [CH₃COOH] = 3a
Then use the formula of Ka, we get
Ka = a * a / 3a = 10^-4.76 ⇔ a = 3 x 10^-4.76 = 5.21 x 10^-5
Hence pH = -log(a) = - log(5.21 x 10^-5) = 4.28
Answer:
The new volume is 87.5 ml.
Explanation:
We have,
Volume of sample of neon is 175 ml
The pressure changed from 75 kPa to 150 kPa.
We need to find new volume.
It is based on the concept of Boyle's law. Let V₂ is new volume. So,
So, new volume is 87.5 ml.
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