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slega [8]
1 year ago
3

If it takes 38.70 cm^3 of 1.90M NaOH to neutralize 10.30cm^3 of H2SO4 in a battery. What is the concentration of the H2SO4?

Chemistry
1 answer:
yKpoI14uk [10]1 year ago
7 0

Answer:

3.57 M

Explanation:

The reaction that takes place is:

  • 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

First we <u>calculate how many NaOH moles reacted</u>, using the<em> given concentration and volume</em>:

  • 38.70 cm³ = 38.70 mL
  • 1.90 M * 38.70 mL = 73.53 mmol NaOH

Then we <u>convert NaOH moles into H₂SO₄ moles</u>, using the <em>stoichiometric coefficients</em>:

  • 73.53 mmol NaOH * \frac{1mmolH_2SO_4}{2mmolNaOH} = 36.765 mmol H₂SO₄

Finally we calculate the concentration of H₂SO₄:

  • 36.765 mmol H₂SO₄ / 10.30 mL = 3.57 M
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When heated, KClO 3 decomposes into KCl and O 2 . 2 KClO 3 ⟶ 2 KCl + 3 O 2 If this reaction produced 71.1 g KCl , how many grams
nata0808 [166]

Answer:

The correct answer is 45.9 g O₂

Explanation:

The descomposition reaction is the following:

2 KClO₃ → 2 KCl + 3 O₂

From this,, we know that 2 mol KClO₃ produce 2 mol of KCl and 3 mol of O₂. Now, we can use the molar mass of the compounds and rewrite the equation with the mass of each compound:

MM KClO₃= 39 g/mol + 35.4 g/mol + (3 x 16 g/mol)= 122.4 g/mol

2 KClO₃ = 2 mol x 122.4 g/mol= 244.8 g

MM KCl= 39 g/mol + 35.4 g/mol= 74.4 g/mol

2 KCl= 2 mol x 74.4 g/mol= 148.8 g

MM O₂= 2 x 16 g/mol= 32 g/mol

3 O₂= 3 mol x 32 g/mol= 96 g

With this, we can write a recipe in mass:

2 KClO₃   →    2 KCl  +    3 O₂

244.8 g    →   148.8 g +  96 g

244.8 g of KClO₃ produce 148.8 g. If we have 71.1 g KCl, the mass of KClO₃ from which this mass of KCl is produced is:

244.8 g KClO₃ ---------------------- 148.8 g KCl

          x             ------------------------ 71.1 g KCl

x= 71.1 g KCl x 244.8 g KClO₃/148.8 g KCl= 116.97 g KClO₃

Finally, we calculate the mass of O₂ produced by 116.97 g of KClO₃ taking into account that the recipe says that 244.8 g of KClO₃ produce 96 g of O₂.

244.8 g KClO₃ ---------------------- 96 g O₂

116.97 g KClO₃----------------------- x= 116.97 g KClO₃ x 96 g O₂/244.8 g KClO₃

x= 45.87 g O₂= 45.9 g O₂

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Explanation:

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