Question

If it takes 38.70 cm^3 of 1.90M NaOH to neutralize 10.30cm^3 of H2SO4 in a battery. What is the concentration of the H2SO4?

Answer 1

Answer:

3.57 M

Explanation:

The reaction that takes place is:

• 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

First we calculate how many NaOH moles reacted, using the given concentration and volume:

• 38.70 cm³ = 38.70 mL

• 1.90 M * 38.70 mL = 73.53 mmol NaOH

Then we convert NaOH moles into H₂SO₄ moles, using the stoichiometric coefficients:

• 73.53 mmol NaOH * $\frac{1mmolH_2SO_4}{2mmolNaOH}$ = 36.765 mmol H₂SO₄

Finally we calculate the concentration of H₂SO₄:

• 36.765 mmol H₂SO₄ / 10.30 mL = 3.57 M