If it takes 38.70 cm^3 of 1.90M NaOH to neutralize 10.30cm^3 of H2SO4 in a battery. What is the concentration of the H2SO4?
1 answer:
Answer:
3.57 M
Explanation:
The reaction that takes place is:
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O First we <u>calculate how many NaOH moles reacted</u>, using the<em> given concentration and volume</em>:
1.90 M * 38.70 mL = 73.53 mmol NaOH Then we <u>convert NaOH moles into H₂SO₄ moles</u>, using the <em>stoichiometric coefficients</em>:
73.53 mmol NaOH * = 36.765 mmol H₂SO₄ Finally we calculate the concentration of H₂SO₄:
36.765 mmol H₂SO₄ / 10.30 mL = 3.57 M
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