Answer:
The incidence angle is 0.145°.
Explanation:
Given that,
Distance due to east = 119 m
Distance due to north= 47.0 km
We need to calculate the incidence angle
Using formula of incidence angle
![\tan\theta=\dfrac{x}{y}](https://tex.z-dn.net/?f=%5Ctan%5Ctheta%3D%5Cdfrac%7Bx%7D%7By%7D)
Where, y = distance due to north
x = distance due to east
Put the value into the formula
![\theta=\tan^{-1}\dfrac{119}{47\times10^3}](https://tex.z-dn.net/?f=%5Ctheta%3D%5Ctan%5E%7B-1%7D%5Cdfrac%7B119%7D%7B47%5Ctimes10%5E3%7D)
![\theta=0.145^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D0.145%5E%7B%5Ccirc%7D)
Hence, The incidence angle is 0.145°.
<span>c). the binding energy per nucleon must decreases as atomic number increases</span>
Answer:
The velocity of the bag will be 16.08 m/s
Explanation:
Given:
Mass of the astronaut, M = 124 kg
Mass of the bag, m = 10 lg
Initial speed of the astronaut with bag,
= 1.20 m/s
Applying the concept of conservation of momentum
we have
(M + m)
= Mv₁ + mv₂
here,
v₁ is the final velocity of the astronaut = 0
v₂ is final velocity of the bag
thus, on substituting the values, we have
(124 + 10)1.20 = 124 × 0 + 10v₂
or
v₂ = 16.08 m/s
Hence, <u>the velocity of the bag will be 16.08 m/s</u>
Very slightly less than 1 g/cm^3 averaged over the entire body.
Even though it doesn't feel like it when you're in the pool, if you completely relax and let go, you do float in water.
Answer:
![P'=\dfrac{P_1P_2}{P_1+P_2}](https://tex.z-dn.net/?f=P%27%3D%5Cdfrac%7BP_1P_2%7D%7BP_1%2BP_2%7D)
Explanation:
Lets take
Resistance of bulb 1 =R₁
Resistance of bulb 2 =R₂
As we know that power P
P= ΔV²/R
Given that voltage difference is same for both bulbs
So
P₁R₁= ΔV² --------1
P₂R₂= ΔV² -----------2
When these resistance are connected in series then equivalent resistance R
R=R₁+ R₂
The new power P'
P'=ΔV²/R
P'R=ΔV² ------3
From equation 1 ,2 and 3
P'(R₁+ R₂) = ΔV²
![P'\left(\dfrac{\Delta V^2}{P_1}+\dfrac{\Delta V^2}{P_2}\right)=\Delta V^2](https://tex.z-dn.net/?f=P%27%5Cleft%28%5Cdfrac%7B%5CDelta%20V%5E2%7D%7BP_1%7D%2B%5Cdfrac%7B%5CDelta%20V%5E2%7D%7BP_2%7D%5Cright%29%3D%5CDelta%20V%5E2)
![P'=\dfrac{P_1P_2}{P_1+P_2}](https://tex.z-dn.net/?f=P%27%3D%5Cdfrac%7BP_1P_2%7D%7BP_1%2BP_2%7D)