Before we could discuss this in any specific detail, I think we would have to
know the angles. A generic discussion without actual numbers for the angles
would be just plain too confusing.
The general approach is that the vertical components of both tensions
add up to 20N, and the horizontal components are equal but in opposite
directions. That's the only way that the mass is hanging motionless.
You have to find the horizontal and vertical components of the tensions
by using the angles and maybe the lengths of the ropes.
Answer:
He could have many different hypothesis, but here is one.
Explanation:
If rubber bands are wider, then the rubber bands will stretch further, because the wider a rubber band is the stronger it is.
The solution to the problem is as follows:
Normal force is m*g plus 240 N*sin30.
<span>30 kg*9.8 m/s^2 + 240 N*sin30 = 414 N
</span>
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Answer:
D) 31 m, 19 Hz
Explanation:
The equation of the wave in the problem is
In general, the equation of a travelling wave is written as
where
A is the amplitude
is the wave number, with being the wavelength of the wave
is the angular frequency and f is the frequency
By comparing the two equations, we see that for this wave:
So now we can use the two equations for k and to find the wavelength and the frequency of the wave: