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jek_recluse [69]
3 years ago
13

Deserts are located in latitude zones which are classified as

Physics
1 answer:
lara31 [8.8K]3 years ago
5 0

Answer: A

Explanation:

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What’s an example of contact friction
kotegsom [21]

Answer:

a nightstand on a lamp table

Explanation:

5 0
3 years ago
A 160.-kilogram space vehicle is traveling along a straight line at a constant speed of 800. Meters per second. The magnitude of
natulia [17]

Answer:

Zero

Explanation:

As force acting on the body is equal to the product of mass and acceleration.

Acceleration is equal to rate of change in velocity.

Here velocity is constant so acceleration is zero.

It means the net force acting on the vehicle is zero.

4 0
3 years ago
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A repelling force occurs between two charged objects when​
fgiga [73]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ It would be 'when they have like charges.'

'Like charges' means the same charge. For example, two positive charged objects have like charges.

<h3><u>✽</u></h3>

➶ Hope This Helps You!

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➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

4 0
3 years ago
Which type of mountain is created when rock layers are pushed up by forces inside the Earth?
skad [1K]

Correct answer choice is :


B) Upwarped


Explanation:


An upwarped mountain is a mountain consisting of a large area of the Earth's coat that has led smoothly upward without much visible deformation and normally including sedimentary, igneous, and metamorphic rocks. Sedimentary rocks are set down in layers called beds or layers. A bed is described as a layer of rock that has a similar lithology and character. Beds form by the removal of layers of sand on top of each other.

7 0
3 years ago
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A particle of mass m collides with a second particle of mass m. Before the collision, the first particle is moving in the x-dire
oee [108]

Answer:

a) v, v

b) 2mv^2

c) Elastic collion

Explanation:

(a) The velocity of the second particle after the collision is (v2x,v2y)=(v,−v).  From momentum conservation in x-direction

Here x, y represent direction.They are not variable. 1 and 2 represent before and after.

2vm=v1xm+v2xm, we find v1x=v.

From momentum conservation in y-direction

0 =v1ym+v2ym, we findv1y=v.

(b) By energy conservation principle

Before: K=1/2m(2v)^2=2mv^2.

After: K=1/2m(v^2(1x)+v^2(1y))+12m(v22x+v22y)=2mv^2

(c) The collision is elastic

6 0
3 years ago
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