Answer:
53.2
Explanation:
The balanced reaction is:
2Fe(s) + 3O₂(g) → Fe₂O₃
It means that 3 moles of oxygen form 1 mol of iron(III) oxide. The molar masses are: Fe = 55.8 g/mol and O = 16 g/mol. So
O₂ = 2x 16 = 32 g/mol
Fe₂O₃ = 2x55.8 + 3x16 = 159.6 g/mol
So, 32 g of O₂ corresponds to 1 mol of O₂. The stoichiometry calculus must be (always in moles):
3 mol of O₂ ------------------------ 1 mol of Fe₂O₃
1 mol of O₂ ------------------------ x
By a direct simple three rule:
3x = 1
x = 1/3 mol of Fe₂O₃
The mass is the molar mass multiplied by the number of moles, so:
m = 159.6x (1/3)
m = 53.2 g iron (III) oxide.
Ca №20
N(e)=20
_______________________
As the atomic mass of iron is 55.847u
We say that it is the mass of one mole of iron.
By formula it can be find by
No.of mole=mass in g/molar mass
Mass in gram = no.of mole x molar mass
No.of mole =1
Molar mass = 55.847g
Mass in gram = 1x55.847
= 55.847g of Fe
The physical properties of matter are going to be appearance,texture, density. hope that helped
Answer:
In the solid phase, the forces of attraction have completely overcome molecular motion, and the movement of the particles has been reduced to vibrating in place. The particles cannot move past one another and are held in a tightly-packed pattern, so there is very little space between the particles.
