You can view more details on each measurement unit: molecular weight of AlCl3 or grams This compound is also known as Aluminium Chloride. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles AlCl3, or 133.340538 grams.
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Answer:
The 150 g Al will reach a higher temperature.
Explanation:
- The amount of heat added to a substance (Q) can be calculated from the relation:
<em>Q = m.c.ΔT.</em>
where, Q is the amount of heat added,
m is the mass of the substance,
c is the specific heat of the substance,
ΔT is the temperature difference (final T - initial T).
Since, Q and c is constant, ΔT will depend only on the mass of the substance (m).
∵ ΔT is inversely proportional to the mass of the substance.
<em>∴ The piece with the lowest mass (150.0 g) will reach a higher temperature than that of a higher mass (250.0 g).</em>
<em>So, the right choice is: The 150 g Al will reach a higher temperature.</em>
Answer:
312 g of O₂
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2KClO₃ —> 2KCl + 3O₂
From the balanced equation above,
2 mole of KClO₃ decomposed to 3 moles of O₂.
Next, we shall determine the number of mole of O₂ produced by the reaction of 6.5 moles of KClO₃. This can be obtained as follow:
From the balanced equation above,
2 mole of KClO₃ decomposed to 3 moles of O₂.
Therefore, 6.5 moles of KClO₃ will decompose to produce = (6.5 × 3)/2 = 9.75 moles of O₂.
Finally, we shall determine the mass of 9.75 moles of O₂. This can be obtained as follow:
Mole of O₂ = 9.75 moles
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ =?
Mole = mass / Molar mass
9.75 = Mass of O₂ / 32
Cross multiply
Mass of O₂ = 9.75 × 32
Mass of O₂ = 312 g
Thus, 312 g of O₂ were obtained from the reaction.
