Answer:
The percent yield is about 66.6%, but with sig figs it's 70%
Explanation:
The formula for percent yield is: (Actual Yield/Theoretical Yield) * 100
1. In order to solve for percent yield, you need both an actual and theoretical yield. This problem gives us an actual yield for H2O, which is 75 grams. Great, you're halfway there!
2. Next, you need to solve for the theoretical yield. In order to do so, you need to set up your stoichiometric ratio.
a) Take your given 100g of O2 and first convert it to moles
b) Then take the O2 in moles and create your mole-to-mole ratio. You're only given 2 values (75g of H2O and 100g of O2), so you know to use O2 and H2O in your ratio. The coefficients are essentially your ratio, so for H2O to O2 it's 2:1
c) Then convert the value from the mole-to-mole ratio back into grams to get your theoretical yield (as values from mole ratios are in moles)
3. Now that you have both your actual and theoretical yields, you can plug it into the equation and solve.
= = 66.60403646
Which is 66.6% when rounded. With sig figs, again, it is 70%
Answer:
ATOMIC number of element A is 3
Explanation:
Atomic number is the same as number of protons of an element.
according to the periodic table, Lithium is the element with 3 protons in its neutral state and it's atomic number is 3.
Answer:
3.43×10¹ mol
Explanation:
Given data:
Initial number of moles = 12.4 mol
Initial volume = 122.8 L
Final number of moles = ?
Final volume = 339.2 L
Solution:
The number of moles and volume are directly proportional to each other at same temperature and pressure.
V₁/n₁ = V₂/n₂
122.8 L/ 12.4 mol = 339.2 L / n₂
n₂ = 339.2 L× 12.4 mol / 122.8 L
n₂ = 4206.08 L.mol /122.8 L
n₂ = 34.3mol
In scientific notation:
3.43×10¹ mol
The amount of sodium bromide that would be formed from the reaction will be 7.5524 grams
<h3>Stoichiometric calculation</h3>
Looking at the equation of the reaction:
The mole ratio of CuBr2 and NaCl is 1:2.
Mole of 16.4 grams of CuBr2 = 16.4/223.37
= 0.0734 moles
Mole of 22.7 grams of NaCl = 22.7/58.44
= 0.3884 moles
Equivalent mole of NaCl = 0.1468 moles
Thus, NaCl is in excess while CuBr2 is limiting.
Mole ratio of CuBr2 and NaBr = 1:1
Mass of 0.0734 mole NaBr = 0.0734 x 102.894
= 7.5524 grams
More on stoichiometric calculation can be found here: brainly.com/question/8062886
Answer:
C. Yes, if each sample contains 6.02 x 10²³ atoms.
Explanation:
It is possible for each sample to contain 1 mole of each sample if and only if each of the sample if made up of 6.02 x 10²³ atoms.
6.02 x 10²³ atoms is the Avogadro's number. This number is equivalent to a mole of a substance.
- If the amount of matter in the given substance is at least one mole, it is possible that they are made up of one mole each of each substance.
- If they contain lesser amount of atoms, then it is not up to one mole of substance.
- But if it is greater, then, we can have even more than one mole of substance.
A mole is simply a unit of measurement and it is equivalent to 6.02 x 10²³ atoms.