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Basile [38]
2 years ago
9

The net force on a vehicle that is accelerating at a rate of 1.5m/s^2 is 1,800 newtons. What is the mass of the vehicle to the n

earest kilogram?
Chemistry
2 answers:
Brilliant_brown [7]2 years ago
8 0

Answer:

Explanation:

Net force F = 1800 N

acceleration a = 1.5 m /s²

mass = m

mass = force / acceleration

= 1800 / 1.5

m = 1200 kg

Anarel [89]2 years ago
6 0

Answer:1200Kg

Explanation:

a = 1.5 m/s2

F = 1800N

M =?

F = Ma

M = F/a = 1800/1.5 = 1200Kg

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You have a solution of 600 mg of caffeine dissolved in 100 mL of water. The partition coefficient for aqueous caffeine extracted
klio [65]

Answer:

159 mg caffeine is being extracted in 60 mL dichloromethane

Explanation:

Given that:

mass of caffeine in 100 mL of water =  600 mg

Volume of the water = 100 mL

Partition co-efficient (K) = 4.6

mass of caffeine extracted = ??? (unknown)

The portion of the DCM = 60 mL

Partial co-efficient (K) = \frac{C_1}{C_2}

where; C_1= solubility of compound in the organic solvent and C_2 = solubility in aqueous water.

So; we can represent our data as:

K=(\frac{A_{(g)}}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL} )

Since one part of the portion is A and the other part is B

A+B = 60 mL

A+B = 0.60

A= 0.60 - B

4.6=(\frac{0.6-B(mg)}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL})

4.6 = \frac{(\frac{0.6-B(mg)}{60mL} )}{(\frac{B_{(mg)}}{100mL})}

4.6 × (\frac{B_{(mg)}}{100mL}) = (\frac{0.6-B(mg)}{60mL} )

4.6 B *\frac{60}{100} = 0.6 - B

2.76 B = 0.6 - B

2.76 + B = 0.6

3.76 B = 0.6

B = \frac{0.6}{3.76}

B = 0.159 g

B = 159 mg

∴ 159 mg caffeine is being extracted from the 100 mL of water containing 600 mg of caffeine with one portion of in 60 mL dichloromethane.

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Antifreeze is mixed with water in a car's cooling system because the solution what?
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Antifreeze is an additive in water-based liquid to lower down the freezing point of such liquid. It is used to make use of the colligative properties of solutions specifically freezing-point depression for cold climate and boiling-point elevation to allow higher coolant temperature.
8 0
3 years ago
Convert this temperature from F to C<br><br> 26.6°c<br> 93.600<br> 62.2°C<br> 5.7°C
eduard
The answer for this is 26.6°c
3 0
2 years ago
g If the titration of a 10.0-mL sample of sulfuric acid requires 28.15 mL of 0.100 M sodium hydroxide, what is the molarity of t
Leona [35]

Answer:

M_{acid}=0.141M

Explanation:

Hello,

In this case, the reaction between sulfuric acid and hydroxide is:

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

We can notice a 1:2 molar ratio between the acid and the base respectively, therefore, at the equivalence point we have:

2*n_{acid}=n_{base}

And in terms of volumes and concentrations:

2*M_{acid}V_{acid}=M_{base}V_{base}

So we compute the molarity of sulfuric acid as shown below:

M_{acid}=\frac{M_{base}V_{base}}{2*V_{acid}} =\frac{0.100M*28.15mL}{2*10.0mL}\\ \\M_{acid}=0.141M

Best regards.

6 0
3 years ago
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