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3 years ago

9

The net force on a vehicle that is accelerating at a rate of 1.5m/s^2 is 1,800 newtons. What is the mass of the vehicle to the n

earest kilogram?

2 answers:

Brilliant_brown [7]3 years ago

8 0

Answer:

Explanation:

Net force F = 1800 N

acceleration a = 1.5 m /s²

mass = m

mass = force / acceleration

= 1800 / 1.5

m = 1200 kg

Anarel [89]3 years ago

6 0

Answer:1200Kg

Explanation:

a = 1.5 m/s2

F = 1800N

M =?

F = Ma

M = F/a = 1800/1.5 = 1200Kg

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25 L of a gas is collected at 115 kPa. If the pressure increases to 300 kPa, what is the new volume?

Lina20 [59]

Answer:

V2 = 9.58 Litres.

Explanation:

Given the following data;

Initial volume = 25 L

Initial pressure = 115 kPa

Final pressure = 300 kPa

To find the new volume V2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

$PV = K$

$P_{1}V_{1} = P_{2}V_{2}$

Substituting into the equation, we have;

$115 * 25 = 300*V_{2}$

$2875 = 300*V_{2}$

$V_{2} = \frac {2875}{300}$

$V_{2} = 9.58$

V2 = 9.58 L

Therefore, the new volume is 9.58 litres.

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3 years ago

Is sweat a chemical? I am curious to know! NO LINKS OR TROLLS

Finger [1]

Answer:

The main reason people perspire is that the evaporation of water can cool our bodies. ... Sweat is chemically similar to plasma, but certain components are selectively retained or excreted.

Explanation:

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3 years ago

When 0.42 g of a compound containing C, H, and O is burned completely, the products are 1.03 g CO2 and 0.14 g H2O. The molecular

Luda [366]

<u>Answer:</u> The empirical and molecular formula for the given organic compound is $C_2H_2O_4$ and $C_6H_4O_2$

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=1.03g$

Mass of $H_2O=0.14g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 1.03 g of carbon dioxide, $\frac{12}{44}\times 1.03=0.28g$ of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 0.14 g of water, $\frac{2}{18}\times 0.14=0.016g$ of hydrogen will be contained.

Mass of oxygen in the compound = (0.42) - (0.28 + 0.016) = 0.124 g

To formulate the empirical formula, we need to follow some steps:

<u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.28g}{12g/mole}=0.023moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.016g}{1g/mole}=0.016moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.124g}{16g/mole}=0.00775moles$

<u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00775 moles.

For Carbon = $\frac{0.023}{0.00775}=2.96\approx 3$

For Hydrogen = $\frac{0.016}{0.00775}=2.06\approx 2$

For Oxygen = $\frac{0.00775}{0.00775}=1$

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 3 : 2 : 1

Hence, the empirical formula for the given compound is $C_3H_{2}O_1=C_3H_2O$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

We are given:

Mass of molecular formula = 108.10 g/mol

Mass of empirical formula = 54 g/mol

Putting values in above equation, we get:

$n=\frac{108.10g/mol}{54g/mol}=2$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(3\times 2)}H_{(2\times 2)}O_{(1\times 2)}=C_6H_4O_2$

Thus, the empirical and molecular formula for the given organic compound is $C_3H_2O$ and $C_6H_4O_2$

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3 years ago

Transpiration is the process by which ____.<br>

saul85 [17]

Answer:

Plants add water to the atmosphere

Explanation:

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3 years ago

Read 2 more answers

Anita did not make the track team this year, and she feels really disappointed and upset. What question would most likely redire

Allushta [10]

Answer:

Anita did not make the track team this year, and she feels really disappointed and upset. What question would most likely redirect her thinking and provide a solution?

Why did this terrible thing happen to me?

What other sports can I try this spring?

Why does everything I attempt go wrong?

Why did Karen get on the team but I didn't?

Answer - What other sports can I try this spring?

Explanation:

Failures and successes are part of our daily lives as humans. It can be very challenging for one to accept his or her failures and bring oneself above it.

when failure occur, the best way to reverse the negative impacts it brings is to move forward and decide on what next to do.

The actions that must be taken in the processes should be quite productive enough to bring back the results one desired.

When the effects of failures prove irreversible, one would then give the mind a diversion and help his or herself think their way though the failure that was encountered.

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3 years ago