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8_murik_8 [283]
3 years ago
11

A gymnast performing a backflip into a cartwheel on a balance beam is am example of ________ force​

Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
8 0
I’m gonna guess equal force sorry if I get it wrong <3
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Why is there DNA in our food?
sukhopar [10]

Answer:

probably because most of our food comes from animals-

Explanation:

3 0
3 years ago
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Calculate the density of sulfuric acid from the information that 35.4 mL of the acid masses 65.14 g.
vladimir1956 [14]

Answer:

<h3>The answer is 1.84 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{65.14}{35.4}  \\  = 1.840112994...

We have the final answer as

<h3>1.84 g/mL</h3>

Hope this helps you

3 0
3 years ago
PLEASE HELP ASAPAHHH
Yanka [14]

Answer:

if the oil is already 60 c and you heat up the hot plate to the same degree you are not changing anything

hope this helps :)

4 0
3 years ago
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How many moles of aspartame are present in 1.00 mg of aspartame?
Diano4ka-milaya [45]

Answer:- There are 3.40*10^-^6 moles.

Solution:- It is a unit conversion problem where we are asked to convert mg of aspartame to moles. Aspartame is C_1_4H_1_8N_2O_5 and it's molar mass is 294.31 grams per mole.

mg are converted to grams and then the grams are converted to moles as:

1.00mg Aspartame(\frac{1g}{1000mg})(\frac{1mole}{294.31g})

= 3.40*10^-^6 moles of aspartame

So, there would be 3.40*10^-^6 moles of aspartame in 1.00 mg of it.

3 0
4 years ago
True or False: In every gram of sucrose (table sugar) there is 0.513 g of oxygen
Ber [7]

Answer:

True

Explanation:

Step 1: Find molecular formula of sucrose

C₁₂H₂₂O₁₁

Step 2: Convert moles of oxygen present to grams

1 mol O = 16 g O

11 mol O = 176 g O

Step 3: Find molar mass of sucrose

C - 12.01 g/mol

H - 1.01 g/mol

O - 16.00 g/mol

12.01(12) + 22(1.01) + 11(16.00) = 342.34 g/mol C₁₂H₂₂O₁₁

Step 4: Set up dimensional analysis

1 gC_{12}H_{22}O_{11}(\frac{176 gO}{342.34gC_{12}H_{22}O_{11}} )

Step 5: Multiply/Divide and cancel out units

Grams of C₁₂H₂₂O₁₁ and grams of C₁₂H₂₂O₁₁ cancel out.

We are left with grams Oxygen

176/342.34 = 0.514109 grams Oxygen

4 0
3 years ago
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