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3 years ago

What is the frequency of a wave when it has a wavelength of 2.17 m and is travelling across a rope at a speed of 31 m/s?

Physics

1 answer:

VikaD [51]3 years ago

4 0

Answer:

i) b. 14.3 Hz

ii) d. 0.4625 m/s

Explanation:

f = c / λ

f = frequency

c = speed

λ = wavelength

first question:

the given values,

λ = 2.17 m

c = 31 m/s

f = c / λ

f = 31 / 2.17

f = 14.28

∴ f = 14.3 Hz

second question:

given,

λ = 0.25 m

f = 1.85 Hz

f = c / λ

rearranging,

c = f × λ

c = 1.85 × 0.25

c = 0.4625

∴ c = 0.4625 m/s

(love your username, btw.)

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Sergio [31]

Answer:

(a) 86.65 J

(b) 149.65 J

Solution:

As per the question:

Diameter of the pool, d = 12 m

⇒ Radius of the pool, r = 6 m

Height of the pool, H = 3 m

Depth of the pool, D = 2.5 m

Density of water, $\rho_{w} = 1000\ kg//m^{3}$

Acceleration due to gravity, g = $9.8\ m/s^{2}$

Now,

(a) Work done in pumping all the water:

Average height of the pool, h = $\frac{H + D}{2}$

h = $\frac{3 + 2.5}{2} = 2.75\ m$

Volume of water in the pool, V = $\pi r^{2}h = \pi \times 6^{2}\times 2.75 = 311.02\ m^{3}$

Mass of water, $m_{w} = \frac{\rho_{w}}{V}$

$m_{w} = \frac{1000}{311.02} = 3.215\ kg$

Work done is given by the potential energy of the water as:

$W = m_{w}gh = 3.215\times 9.8\times 2.75 = 86.65\ J$

(b) Work done to pump all the water through an outlet of 2 m:

Now,

Height, h = 2.75 + 2 = 4.75

Work done, $W = m_{w}gh = 3.215\times 9.8\times 4.75 = 149.65\ J$

7 0

3 years ago

Need help with the questons asap

mina [271]

Which questions? i need to see the actual question, did you like upload them to your profile now?

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3 years ago

Breathing on a cold window can cause it to fog up. which change of state causes this

Dominik [7]

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Condensation is: The process in which molecules of a gas slow down, come together, and form a liquid water that collects as droplets on a cold surface when humid air is in contact with it.

I know this because I learned it in science class in school.

Hope I helped!

- Debbie

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A student is working in a lab to determine how time affects impulse. The student keeps the force the same in each trial but chan

pishuonlain [190]

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3 years ago

Read 2 more answers

A golf club hits a 0.04551 kg golf ball off a golf tee. The club is in contact with the ball for 0.020 s, and the force applied

Juliette [100K]

Answer:

v = 50.5 m/s

Explanation:

F = (m)(^v/^t)

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2,526.917161 m/s² = v/(0.020s)

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