Question

What angle would the axis of a polarizing filter need to make with the direction of polarized light of intensity 1.00 kW/m2 to reduce the intensity to 10.0 W/m2

Answer 1

Answer:

The angle is 84.26⁰

Explanation:

The angle the axis of a polarizing filter need to make with the direction of polarized light is given by;

I = I₀Cos²θ

where;

I is the intensity of the polarized light transmitted from the polarizer

I₀ is the intensity of the polarized light incident on the polarizer

Given;

I₀ = 1.00 kW/m² = 1000 W/m²

I = 10 W/m²

$Cos^2 \theta = \frac{I}{I_o}\\\\Cos \theta = \sqrt{\frac{I}{I_o}}\\\\\theta = Cos^{-1}( \sqrt{\frac{I}{I_o}})\\\\\theta = Cos^{-1}( \sqrt{\frac{10}{1000}})\\\\\theta = 84.26^0$

Therefore, the angle is 84.26⁰