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steposvetlana [31]
3 years ago
11

If you have 730 moles of a gas at 304 Kelvin in a 4.50 Liter container what

Chemistry
1 answer:
vova2212 [387]3 years ago
3 0

Answer:

4046atm

Explanation:

For this question you can use the ideal gas law,

<em />PV=nRT<em />

Where P is pressure, V is volume, n is moles of substance, R is the constant, and T is the temperature.

Because of the units given, R will equal .08026P=4046 atm

<h3>Rearrange the equation to solve for pressure:</h3>

P=\frac{nRT}{V}

Then, plug in the values (I'll be excluding units for simplicity, but they all cancel out for pressure in atm):

P=\frac{(730)(.08206)(304)}{4.5}

This will give you:

P=4046atm

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A chemist makes of magnesium fluoride working solution by adding distilled water to of a stock solution of magnesium fluoride in
mojhsa [17]

The question is incomplete, here is the complete question:

A chemist makes 600. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a stock solution of 0.00154 mol/L magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.

<u>Answer:</u> The concentration of chemist's working solution is 5.90\times 10^{-4}M

<u>Explanation:</u>

To calculate the molarity of the diluted solution (chemist's working solution), we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock magnesium fluoride solution

M_2\text{ and }V_2 are the molarity and volume of chemist's magnesium fluoride solution

We are given:

M_1=0.00154M\\V_1=230mL\\M_2=?M\\V_2=600mL

Putting values in above equation, we get:

0.00154\times 230=M_2\times 600\\\\M_2=\frac{0.00154\times 230}{600}=5.90\times 10^{-4}M

Hence, the concentration of chemist's working solution is 5.90\times 10^{-4}M

8 0
3 years ago
I have a balloon that can hold 125,000 mL of air. If I blow up this balloon with 3 moles of oxygen gas at a
matrenka [14]

Answer:

234.35 °C

Explanation:

Given data:

Volume of balloon = 125000 mL

Moles of oxygen = 3 mol

Pressure = 1 atm

Temperature = ?

Solution:

Formula:

PV = nRT

P = Pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

Volume of balloon = 125000 mL × 1 L /1000 mL

Volume of balloon = 125 L

Now we will put the values:

Ideal gas constant = R = 0.0821 atm.L/mol.K

PV = nRT

T = PV/nR

T = 1 atm × 125 L/  0.0821 atm.L/mol.K × 3 mol

T= 125  /0.2463 /K

T = 507.5 K

K to °C

507.5 K - 273.15 = 234.35 °C

4 0
3 years ago
Which alkane would have a higher boiling point?a)ethaneb)pentanec)heptane
Whitepunk [10]

Answer:

The correct answer is option c.

Explanation:

Alkanes with higher molecular mass has higher boiling point.

Thisis because when the molar mass of the alkanes increases the the surface area  increases with which van der Waals forces between the molecules of alkane also increase which increases the association of the molecules of with each other which results in increase in boiling point is observed.

The increasing order of the molar mass of the given alkanes;

C_2H_6

So out of ethane, pentane and heptane . Heptane has highest molecular mass with higher boiling point value. Where as ethane have the lowest value of boiling point.

6 0
4 years ago
Cuanto equivale 1000 yardas a 1 pie, 1 metro y 1 centímetro
Charra [1.4K]

Respuesta:

3000 ft

914.4 m

9.144 × 10⁴ cm

Explicación:

Paso 1: Información provista

Longitud: 1000 yd

Paso 2: Convertir 1000 yd a pies (ft)

Usaremos el factor de conversion 1 yd = 3 ft.

1000 yd × 3 ft/1 yd = 3000 ft

Paso 3: Convertir 1000 yd a metros (m)

Usaremos el factor de conversion 1 yd = 0.9144 m.

1000 yd × 0.9144 m/1 yd = 914.4 m

Paso 4: Convertir 914.4 m a centimetros (cm)

Usaremos el factor de conversion 1 m  = 100 cm.

914.4 m × 100 cm/ 1 m = 9.144 × 10⁴ cm

5 0
3 years ago
Rank the compounds below from slowest to Fastest rate of hydration. 1) formaldehyde 2) 3,3-dimethyIbutan-2-one 3) propanal 4)3-m
Makovka662 [10]

Answer:

5,3,4,1,2 this is your answer.

7 0
3 years ago
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